或多或少在它上面说的:在Python中有一种(简单的)方法可以列出Windows系统中当前正在使用的所有驱动器号吗?
(我的google-fu似乎让我失望了。)
相关:
答案 0 :(得分:56)
不使用任何外部库,如果这对您很重要:
import string
from ctypes import windll
def get_drives():
drives = []
bitmask = windll.kernel32.GetLogicalDrives()
for letter in string.uppercase:
if bitmask & 1:
drives.append(letter)
bitmask >>= 1
return drives
if __name__ == '__main__':
print get_drives() # On my PC, this prints ['A', 'C', 'D', 'F', 'H']
答案 1 :(得分:54)
import win32api
drives = win32api.GetLogicalDriveStrings()
drives = drives.split('\000')[:-1]
print drives
改编自: http://www.faqts.com/knowledge_base/view.phtml/aid/4670
答案 2 :(得分:8)
那些看起来更好的答案。这是我的hackish cruft
import os, re
re.findall(r"[A-Z]+:.*$",os.popen("mountvol /").read(),re.MULTILINE)
在RichieHindle的答案上稍微嗤之以鼻;它并不是真的更好,但你可以让窗户做出实际的字母表字母的工作
>>> import ctypes
>>> buff_size = ctypes.windll.kernel32.GetLogicalDriveStringsW(0,None)
>>> buff = ctypes.create_string_buffer(buff_size*2)
>>> ctypes.windll.kernel32.GetLogicalDriveStringsW(buff_size,buff)
8
>>> filter(None, buff.raw.decode('utf-16-le').split(u'\0'))
[u'C:\\', u'D:\\']
答案 3 :(得分:8)
Microsoft Script Repository包括this recipe,这可能有所帮助。我没有Windows机器来测试它,所以我不确定你是否想要“名称”,“系统名称”,“卷名”或其他东西。
import win32com.client
strComputer = "."
objWMIService = win32com.client.Dispatch("WbemScripting.SWbemLocator")
objSWbemServices = objWMIService.ConnectServer(strComputer,"root\cimv2")
colItems = objSWbemServices.ExecQuery("Select * from Win32_LogicalDisk")
for objItem in colItems:
print "Access: ", objItem.Access
print "Availability: ", objItem.Availability
print "Block Size: ", objItem.BlockSize
print "Caption: ", objItem.Caption
print "Compressed: ", objItem.Compressed
print "Config Manager Error Code: ", objItem.ConfigManagerErrorCode
print "Config Manager User Config: ", objItem.ConfigManagerUserConfig
print "Creation Class Name: ", objItem.CreationClassName
print "Description: ", objItem.Description
print "Device ID: ", objItem.DeviceID
print "Drive Type: ", objItem.DriveType
print "Error Cleared: ", objItem.ErrorCleared
print "Error Description: ", objItem.ErrorDescription
print "Error Methodology: ", objItem.ErrorMethodology
print "File System: ", objItem.FileSystem
print "Free Space: ", objItem.FreeSpace
print "Install Date: ", objItem.InstallDate
print "Last Error Code: ", objItem.LastErrorCode
print "Maximum Component Length: ", objItem.MaximumComponentLength
print "Media Type: ", objItem.MediaType
print "Name: ", objItem.Name
print "Number Of Blocks: ", objItem.NumberOfBlocks
print "PNP Device ID: ", objItem.PNPDeviceID
z = objItem.PowerManagementCapabilities
if z is None:
a = 1
else:
for x in z:
print "Power Management Capabilities: ", x
print "Power Management Supported: ", objItem.PowerManagementSupported
print "Provider Name: ", objItem.ProviderName
print "Purpose: ", objItem.Purpose
print "Quotas Disabled: ", objItem.QuotasDisabled
print "Quotas Incomplete: ", objItem.QuotasIncomplete
print "Quotas Rebuilding: ", objItem.QuotasRebuilding
print "Size: ", objItem.Size
print "Status: ", objItem.Status
print "Status Info: ", objItem.StatusInfo
print "Supports Disk Quotas: ", objItem.SupportsDiskQuotas
print "Supports File-Based Compression: ", objItem.SupportsFileBasedCompression
print "System Creation Class Name: ", objItem.SystemCreationClassName
print "System Name: ", objItem.SystemName
print "Volume Dirty: ", objItem.VolumeDirty
print "Volume Name: ", objItem.VolumeName
print "Volume Serial Number: ", objItem.VolumeSerialNumber
答案 4 :(得分:7)
在Google上找到此解决方案,稍有修改。貌似漂亮的pythonic,不需要任何“异国情调”的进口
import os, string
available_drives = ['%s:' % d for d in string.ascii_uppercase if os.path.exists('%s:' % d)]
答案 5 :(得分:4)
我写了这段代码:
import os
drives = [ chr(x) + ":" for x in range(65,90) if os.path.exists(chr(x) + ":") ]
它基于@ Barmaley的回答,但具有不使用string
的优势
模块,以防您不想使用它。它也适用于我的系统,不像@ SingleNegationElimination的答案。
答案 6 :(得分:3)
基于@RichieHindle的更佳解决方案
def get_drives():
drives = []
bitmask = windll.kernel32.GetLogicalDrives()
letter = ord('A')
while bitmask > 0:
if bitmask & 1:
drives.append(chr(letter) + ':\\')
bitmask >>= 1
letter += 1
return drives
答案 7 :(得分:3)
在Windows上,您可以执行os.popen
import os
print os.popen("fsutil fsinfo drives").readlines()
答案 8 :(得分:1)
这是我的更高性能方法(可能更高):
>>> from string import ascii_uppercase
>>> reverse_alphabet = ascii_uppercase[::-1]
>>> from ctypes import windll # Windows only
>>> GLD = windll.kernel32.GetLogicalDisk
>>> drives = ['%s:/'%reverse_alphabet[i] for i,v in enumerate(bin(GLD())[2:]) if v=='1']
没有人真正使用python的表演性功能......
是的,我没有遵循Windows标准路径约定('\\')...
在使用python的所有这些年里,我在使用任何路径的'/'方面没有任何问题,并且在我的程序中使它成为标准。
答案 9 :(得分:1)
如果您只想列出光盘上的驱动器而不是列出的网络驱动器,那么这是另一个很棒的解决方案。如果要按不同的属性进行过滤,只需打印drps。
import psutil
drps = psutil.disk_partitions()
drives = [dp.device for dp in drps if dp.fstype == 'NTFS']
答案 10 :(得分:1)
此代码将返回驱动器名称和字母的列表,例如:
['Gateway(C :)','EOS_DIGITAL(L :)','Music Archive(O:)']
它仅使用标准库。它基于我在上面发现的一些想法。 如果磁盘驱动器为空,则windll.kernel32.GetVolumeInformationW()返回0,例如,没有磁盘的CD ROM。此代码未列出这些空驱动器。
这两行记录了所有驱动器的字母:
bitmask = (bin(windll.kernel32.GetLogicalDrives())[2:])[::-1] # strip off leading 0b and reverse
drive_letters = [ascii_uppercase[i] + ':/' for i, v in enumerate(bitmask) if v == '1']
这是完整的例程:
from ctypes import windll, create_unicode_buffer, c_wchar_p, sizeof
from string import ascii_uppercase
def get_win_drive_names():
volumeNameBuffer = create_unicode_buffer(1024)
fileSystemNameBuffer = create_unicode_buffer(1024)
serial_number = None
max_component_length = None
file_system_flags = None
drive_names = []
# Get the drive letters, then use the letters to get the drive names
bitmask = (bin(windll.kernel32.GetLogicalDrives())[2:])[::-1] # strip off leading 0b and reverse
drive_letters = [ascii_uppercase[i] + ':/' for i, v in enumerate(bitmask) if v == '1']
for d in drive_letters:
rc = windll.kernel32.GetVolumeInformationW(c_wchar_p(d), volumeNameBuffer, sizeof(volumeNameBuffer),
serial_number, max_component_length, file_system_flags,
fileSystemNameBuffer, sizeof(fileSystemNameBuffer))
if rc:
drive_names.append(f'{volumeNameBuffer.value}({d[:2]})') # disk_name(C:)
return drive_names
答案 11 :(得分:0)
作为类似任务的一部分,我还需要获取免费的驱动器号。我决定要收到最高的信件。我首先用惯用语写出来,然后把它碾成1个衬里,看看它是否仍然有意义。正如列表理解一样令人敬畏,我喜欢这样设置:unused=set(alphabet)-set(used)
而不是必须unused = [a for a in aphabet if a not in used]
。很酷的东西!
def get_used_drive_letters():
drives = win32api.GetLogicalDriveStrings()
drives = drives.split('\000')[:-1]
letters = [d[0] for d in drives]
return letters
def get_unused_drive_letters():
alphabet = map(chr, range(ord('A'), ord('Z')+1))
used = get_used_drive_letters()
unused = list(set(alphabet)-set(used))
return unused
def get_highest_unused_drive_letter():
unused = get_unused_drive_letters()
highest = list(reversed(sorted(unused)))[0]
return highest
一个班轮:
def get_drive():
highest = sorted(list(set(map(chr, range(ord('A'), ord('Z')+1))) -
set(win32api.GetLogicalDriveStrings().split(':\\\000')[:-1])))[-1]
我还使用map / range / ord / chr选择使用字符串的字母表,因为部分字符串已被弃用。
答案 12 :(得分:0)
由于我没有在我的笔记本电脑领域安装win32api,我使用wmic来解决这个问题:
import subprocess
import string
#define alphabet
alphabet = []
for i in string.ascii_uppercase:
alphabet.append(i + ':')
#get letters that are mounted somewhere
mounted_letters = subprocess.Popen("wmic logicaldisk get name", shell=True, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
#erase mounted letters from alphabet in nested loop
for line in mounted_letters.stdout.readlines():
if "Name" in line:
continue
for letter in alphabet:
if letter in line:
print 'Deleting letter %s from free alphabet %s' % letter
alphabet.pop(alphabet.index(letter))
print alphabet
或者你可以从这两个列表中获得差异,就像这个更简单的解决方案(在启动wmic子进程作为mounted_letters之后):
#get output to list
mounted_letters_list = []
for line in mounted_letters.stdout.readlines():
if "Name" in line:
continue
mounted_letters_list.append(line.strip())
rest = list(set(alphabet) - set(mounted_letters_list))
rest.sort()
print rest
两种解决方案同样快速,但我认为设置列表出于某种原因更好,对吧?
答案 13 :(得分:0)
如果您不想担心跨平台问题,包括跨越Pypy等python平台的问题,并且希望在运行时更新驱动器时使用性能良好的东西:
>>> from os.path import exists
>>> from sys import platform
>>> drives = ''.join( l for l in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' if exists('%s:/'%l) ) if platform=='win32' else ''
>>> drives
'CZ'
这是我对此代码的性能测试:
4000 iterations; threshold of min + 250ns:
__________________________________________________________________________________________________________code___|_______min______|_______max______|_______avg______|_efficiency
⡇⠀⠀⢀⠀⠀⠀⠀⠀⡄⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⣷⣷⣶⣼⣶⣴⣴⣤⣤⣧⣤⣤⣠⣠⣤⣤⣶⣤⣤⣄⣠⣦⣤⣠⣤⣤⣤⣤⣄⣠⣤⣠⣤⣤⣠⣤⣤⣤⣤⣤⣤⣄⣤⣤⣄⣤⣄⣤⣠⣀⣀⣤⣄⣤⢀⣀⢀⣠⣠⣀⣀⣤⣀⣠
drives = ''.join( l for l in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' if exists('%s:/'%l) ) if platform=='win32' else '' | 290.049ns | 1975.975ns | 349.911ns | 82.892%
答案 14 :(得分:0)
这是一个简单的版本,没有安装任何其他模块或功能。
>>> import os
>>> ['%s:' % d for d in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' if os.path.exists('%s:' % d)]
['C:', 'D:']
来源:https://bytes.com/topic/python/answers/802661-list-disk-drives-windows
答案 15 :(得分:0)
这将有助于在Windows操作系统中找到有效的驱动器
import os
import string
drive = string.ascii_uppercase
valid_drives = []
for each_drive in drive:
if os.path.exist(each_drive+":\\"):
print(each_drive)
valid_drives.append(each_drive+":\\")
print(valid_drives)
输出将是
C
D
E
['C:\\','D:\\','E:\\']
答案 16 :(得分:0)
如果只需要每个驱动器的字母,则可以:
from win32.win32api import GetLogicalDriveStrings
drives = [drive for drive in GetLogicalDriveStrings()[0]]