Question

我是SQL服务器的新手。

我有下表：

id  dayoftheweek    timeoftheday
1   mondayOpen  0:00 
1   mondayClose 23:59
1   tuesdayOpen 0:00
1   tuesdayClose    23:59
1   wednesdayOpen   0:00
1   wednesdayClose  23:59
1   thursdayOpen    0:00
1   thursdayClose   23:59
1   fridayOpen  0:00
1   fridayClose 23:59
1   saturdayOpen    0:00
1   saturdayClose   23:59
1   sundayOpen  0:00
1   sundayClose 23:59

我想要以下内容：

     id day     open   close
     1  monday  0:00   23:59
     2  tuesday 0:00   23:59

我不知道是否需要编写一个sproc（T-SQL）或者SQL中是否有任何内置关键字，使用它我可以得到我想要的输出。我无法创建新表，但在我现有的架构中允许使用视图。

请帮帮我。

TIA

Answer 1

表格结构很可怕，我会做任何你能做的事情来摆脱它。那就是说mssql有一些你可以使用的子串函数。

select dayoftheweek, timeoftheday 'open'
from uglytable
where right(dayofweek,4) = 'Open'

这将为您提供所有已打开的记录。我们会做同样的事情，以便在一秒钟内获得所有已关闭的记录。这将是阅读开放与封闭

的挑战

要解决的第二个问题是从该文本中选择“日期”列。每天都以y结尾，其中不包含其他'y'，所以我们可以使用charindex

lil免责声明......我没有可用于测试的mssql数据库，所以我可能会在这里和那里成为一个字符。

 select charindex('y',dayoftheweek)

这将返回'y'字符的字符串中的位置。

Mondayopen在第6个角色上有一个y

select left('mondayopen',6)

这将返回mondayOpen或mondayClose的左侧6个字符。把两者放在一起：

select left(dayoftheweek,charindex('y',dayoftheweek))

希望我做对了......它应该是mondayopen和mondayclose到星期一。把两者放在一起：

select left(dayoftheweek,charindex('y',dayoftheweek)) dayofweek, timeoftheday 'open'
from uglytable
where right(dayofweek,4) = 'Open'

现在应该在没有'开放'或'关闭'以及开放时间的情况下返回每周一天。将其转换为子查询，将其连接到close子查询并放在一起：

select open.dayofweek, open.open,close.close
from
(select left(dayoftheweek,charindex('y',dayoftheweek)) dayofweek, timeoftheday 'open'
from uglytable
where right(dayofweek,4) = 'Open')  open
inner join
(select left(dayoftheweek,charindex('y',dayoftheweek)) dayofweek, timeoftheday 'close'
from uglytable
where right(dayofweek,5) = 'Close')  close
on open.dayofweek = close.dayofweek

希望我没有语法错误，没有什么可以测试它，可能会有错误^^

Answer 2

当然，这是非常糟糕的数据库设计。用于存储您需要在DATE and TIME类型上使用的日期。

试试这个：

declare @tbl table(id int,  dayoftheweek varchar(50), timeoftheday varchar(10))
insert into @tbl values (1,   'mondayOpen',  '0:00') 
insert into @tbl values (1,   'mondayClose',  ' 23:59')
insert into @tbl values (1,   'tuesdayOpen',  ' 0:00')
insert into @tbl values (1,   'tuesdayClose',   ' 23:59')
insert into @tbl values (1,   'wednesdayOpen',   '0:00')
insert into @tbl values (1,   'wednesdayClose',  '23:59')
insert into @tbl values (1,   'thursdayOpen',   ' 0:00')
insert into @tbl values (1,   'thursdayClose',   '23:59')
insert into @tbl values (1,   'fridayOpen',  '0:00')
insert into @tbl values (1,   'fridayClose',  '23:59')
insert into @tbl values (1,   'saturdayOpen',   ' 0:00')
insert into @tbl values (1,   'saturdayClose',   '23:59')
insert into @tbl values (1,   'sundayOpen',  '0:00')
insert into @tbl values (1,   'sundayClose',  '23:59')
insert into @tbl values (2,   'mondayOpen',  '0:00') 
insert into @tbl values (2,   'mondayClose',  ' 23:59')
insert into @tbl values (2,   'tuesdayOpen',  ' 0:00')
insert into @tbl values (2,   'tuesdayClose',   ' 23:59')
insert into @tbl values (2,   'wednesdayOpen',   '0:00')
insert into @tbl values (2,   'wednesdayClose',  '23:59')
insert into @tbl values (2,   'thursdayOpen',   ' 0:00')


SELECT tOpen.id, tOpen.DayOfTheWeek, tOpen.timeoftheday OpenTime, tClose.timeoftheday CloseTime
FROM (SELECT REPLACE(dayoftheweek,'open','') DayOfTheWeek,  timeoftheday,id
      FROM @tbl
      WHERE LEN(REPLACE(dayoftheweek,'open',''))<LEN(dayoftheweek)) tOpen
      JOIN
      (SELECT REPLACE(dayoftheweek,'close','') DayOfTheWeek,  timeoftheday,id
      FROM @tbl
      WHERE LEN(REPLACE(dayoftheweek,'close',''))<LEN(dayoftheweek)) tClose ON tOpen.DayOfTheWeek=tClose.DayOfTheWeek AND tOpen.id=tClose.id

制作具有挑战性的SQL查询

2 个答案: