Question

编辑2

谢谢大家的帮助！通过融合答案和其他一些论坛帖子，我设法通过以下方式解决：

$string = strip_tags($oNode['div.item-prijs']);
$array = str_split($string,1); 
$arraytotal = ( $array[0] . ',' . $array[1] . $array[2] );
echo $arraytotal;

现在显示正确的价格。 “7,49”我自动转换为的PHP脚本。

很抱歉，我无法提供更多问题回答标记。案件已结案。

加油人

$price = strip_tags($oNode['div.item-prijs']);
$new_price = substr(chunk_split($price, 1, ','), 0, -1); 
echo $new_price;

这将回显7,4,9而不是7,49。但是这段代码是目前为止最好的代码。有人知道如何解决这个问题吗？

我现在已经坚持了一段时间..

我正在从网站解析数据，我想得到价格，但在网站上没有逗号或价格之间的点。因此它显示为499，4大于99。

当我这样做时：

$price = $oNode['div.item-prijs'];
echo $price;

它将回应499。我希望它添加逗号或4到99之间的点。

我试过了：

$price = $oNode['div.item-prijs'];
$new_price = substr(chunk_split($price, 1, ','), 0, -1); 
echo $new_string;

这将回应：

<,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,7,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,4,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,0,<,s,u,p,>,6,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,6,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,1,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,8,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,2,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,0,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,2,<,s,u,p,>,2,5,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,0,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,5,4,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,2,<,s,u,p,>,0,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,7,8,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,7,1,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,0,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,2,<,s,u,p,>,0,8,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,1,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,4,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,6,<,s,u,p,>,1,8,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,3,<,s,u,p,>,9,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,4,<,s,u,p,>,2,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,><,d,i,v, ,c,l,a,s,s,=,",i,t,e,m,-,p,r,i,j,s,",>,<,p,>,2,<,s,u,p,>,7,9,<,/,s,u,p,>,<,/,p,>,<,/,d,i,v,>

而且：

$string = $oNode['div.item-prijs'];
    $new_string = substr(chunk_split($string, 4, ','), 0, -1); 
    echo $new_string;

这将回应：

,
7,49<,/sup,>,

<,/p><,/div,>,

4,99<,/sup,>,

1,49<,/sup,>,

0,69<,/sup,>,

1,99<,/sup,>,

1,49<,/sup,>,

1,49<,/sup,>,

3,49<,/sup,>,

3,49<,/sup,>,

3,69<,/sup,>,

1,19<,/sup,>,

1,89<,/sup,>,

1,99<,/sup,>,

1,99<,/sup,>,

1,49<,/sup,>,

2,99<,/sup,>,

1,99<,/sup,>,

1,09<,/sup,>,

2,25<,/sup,>,

1,99<,/sup,>,

0,99<,/sup,>,

1,54<,/sup,>,

2,09<,/sup,>,

1,78<,/sup,>,

1,71<,/sup,>,

0,99<,/sup,>,

1,49<,/sup,>,

2,08<,/sup,>,

1,49<,/sup,>,

3,49<,/sup,>,

6,18<,/sup,>,

3,99<,/sup,>,

4,29<,/sup,>,

2,79<,/sup,>

所以它会扼杀页面上的每个价格，但也会回显html代码。它拆分html代码而不是价格。

以下是网站上的HTML代码

<div class="item-prijs">
        <p>
            <cufon class="cufon cufon-canvas" alt="4" style="width: 27px; height: 42px; ">
                <canvas width="47" height="43" style="width: 47px; height: 43px; top: -1px; left: -2px; "></canvas>
                <cufontext>4</cufontext>
            </cufon>
            <sup>
                <cufon class="cufon cufon-canvas" alt="99" style="width: 24px; height: 20px; ">
                    <canvas width="35" height="21" style="width: 35px; height: 21px; top: -1px; left: -1px; ">
                    </canvas><cufontext>99</cufontext>
                </cufon>
            </sup>
        </p>
    </div>

我做错了什么？我尝试了不同的方法，但没有成功。有人可以用正确的代码帮助我吗？

由于

Answer 1

简单解决方案发生了什么？

$major = intval($price / 100);
$minor = intval($price) % 100;

echo "The price is $major.$minor.\n";

甚至：

echo "The price is " . ($price / 100) ".\n";

（如果您对默认的浮动格式感到满意。）

Answer 2

试试这个，添加strip_tags它会删除所有HTML标记：

$price = strip_tags($oNode['div.item-prijs']);
$new_price = substr(chunk_split($price, 1, ','), 0, -1); 
echo $new_string;

Answer 3

鉴于它是phpQuery你可以使用：

echo trim ($oNode['div.item-prijs']->text ());

获取实际数据。

但这可能更接近你所追求的目标：

$price = array ();
foreach ($oNode['div.item-prijs cufontext'] as $n)
{
        $price[] = (int )pq ($n)->text ();
}

它将产生一个数组 - 在这种情况下 - 两个元素，4和99。

<强>更新：

要按照您想要的方式打印价格，请使用：

echo $price[0] . '.' . $price[1];

更新2 ：

phpQuery选择应该看起来像这样：

foreach (pq ($oNode)->find ('div.item-prijs') as $price_node)
{
    // we're iterating each <div /> class 'item-prijs'.
    $price = array ();
    foreach (pq ($price_node)->find ('cufontext') as $pn)
    {
      // iterate each <cufontext /> child node to div.item-prijs
      $price[] = (int )pq ($n)->text ();
    }

    // we could add $price to an array or something, but we'll just echo for now.
    echo $price[0] . '.' . $price[1] . "\n";
}

这将迭代每个div.item-prijs并将价格提取到数组$ price。

Answer 4

也许这会解决你的问题;

$price = $oNode['div.item-prijs'];
$new_price = substr(chunk_split($price, 1, ','), 0, -1); 
echo $new_price; // not $new_string; I think $new_string is an other var in your code

但您也会在代码中解析<sup>标记。

你能试试吗？

$preg='#<div class="item-prijs"><p>(.*?)<sup>(.*?)</sup></p></div>#si'; 
preg_match_all($preg,$new_string,$number,PREG_SET_ORDER);

$ numbers [0]是逗号之前的数字数组

$ numbers [1]是逗号后的数字数组

MAybe这有帮助;

$string = $oNode['div.item-prijs']; 
$new_string = substr(chunk_split($string, 4, ','), 0, -1);
echo str_replace("<,/sup,>,", "", $new_string);

Answer 5

如果我正确理解了问题，您可以剥离标记，将价格乘以10，然后使用number_format。之后你只需要删除最后一位数字。

php -r 'echo substr(number_format((499*10)), 0, -1);' => 4,99
php -r 'echo substr(number_format((599*10)), 0, -1);' => 5,99
php -r 'echo substr(number_format((5099*10)), 0, -1);' => 50,99

带逗号的小数位数或第一个数字后的点数

5 个答案: