Question

我想弹出导航堆栈上的第三个视图回到第一个视图。

我知道如何一次弹出一个视图：

[self.navigationController popViewControllerAnimated:YES];

但我怎么一次做两个呢？

...谢谢

Answer 1

您可以尝试在导航控制器堆栈之间跳转

NSMutableArray *allViewControllers = [NSMutableArray arrayWithArray:[self.navigationController viewControllers]];
for (UIViewController *aViewController in allViewControllers) {
    if ([aViewController isKindOfClass:[RequiredViewController class]]) {
        [self.navigationController popToViewController:aViewController animated:NO];
    }
}

Answer 2

以下是两个可以解决您问题的UINavigationController扩展程序。我建议使用弹出到特定类UIViewController的第一个：

extension UINavigationController {

  func popToViewController(ofClass: AnyClass, animated: Bool = true) {
    if let vc = viewControllers.filter({$0.isKind(of: ofClass)}).last {
      popToViewController(vc, animated: animated)
    }
  }

  func popViewControllers(viewsToPop: Int, animated: Bool = true) {
    if viewControllers.count > viewsToPop {
      let vc = viewControllers[viewControllers.count - viewsToPop - 1]
      popToViewController(vc, animated: animated)
    }
  }

}

并像这样使用它：

// pop to SomeViewController class
navigationController?.popToViewController(ofClass: SomeViewController.self)

// pop 2 view controllers
navigationController?.popViewControllers(viewsToPop: 2)

Answer 3

您可以使用popToRootViewControllerAnimated：

弹出“root”（第一个）视图控制器

[self.navigationController popToRootViewControllerAnimated:YES];

// If you want to know what view controllers were popd:
// NSArray *popdViewControllers = [self.navigationController popToRootViewControllerAnimated:YES];

UINavigationController Reference：

弹出除根视图控制器之外的堆栈上的所有视图控制器并更新显示。

返回值
  从堆栈中弹出的一组视图控制器。

Answer 4

[self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:1] animated:YES];

objectAtIndex：1 - ＆gt;你可以传递你想要弹出的索引

Answer 5

Swift 2 - xCode 7.3

这可能是弹出UIViewControllers的一个非常有用的扩展：

extension UINavigationController {

    func popToViewControllerOfType(classForCoder: AnyClass) {
        for controller in viewControllers {
            if controller.classForCoder == classForCoder {
                popToViewController(controller, animated: true)
                break
            }
        }
    }

    func popViewControllers(controllersToPop: Int, animated: Bool) {
        if viewControllers.count > controllersToPop {
            popToViewController(viewControllers[viewControllers.count - (controllersToPop + 1)], animated: animated)
        } else {
            print("Trying to pop \(controllersToPop) view controllers but navigation controller contains only \(viewControllers.count) controllers in stack")
        }
    }
}

Answer 6

如果你只是想一次弹出2因为你的rootViewController（更深）'然后2你可以考虑在UIviewController中添加一个类别，例如：

的UINavigationController + popTwice.h

#import <UIKit/UIKit.h>
@interface UINavigationController (popTwice)

- (void) popTwoViewControllersAnimated:(BOOL)animated;

@end

的UINavigationController + popTwice.m

#import "UINavigationController+popTwice.h"

@implementation UINavigationController (popTwice)

- (void) popTwoViewControllersAnimated:(BOOL)animated{
    [self popViewControllerAnimated:NO];
    [self popViewControllerAnimated:animated];
}

@end

在您的实现中的某处导入类别#import "UINavigationController+popTwice.h"，并使用此行代码一次弹出2个控制器：

[self.navigationController popTwoViewControllersAnimated:YES];

不是很好吗？：）

Answer 7

//viewIndex = 1;
//viewIndex = 2;
//viewIndex = 3;

// **[viewControllers objectAtIndex: *put here your viewindex number*]

NSArray *viewControllers = [self.navigationController viewControllers];
[self.navigationController popToViewController:[viewControllers objectAtIndex:viewIndex] animated:NO];

Answer 8

你也可以尝试这个： -

[self.navigationController popToViewController:yourViewController animated:YES];

Answer 9

    NSMutableArray *newStack = [NSMutableArray arrayWithArray:[self.navigationController viewControllers]];
    [newStack removeLastObject];
    [newStack removeLastObject];
    [self.navigationController setViewControllers:newStack animated:YES];

Answer 10

在Swift 3中，您可以从导航控制器中弹出一个，两个或更多个视图控制器，如

let viewControllers = self.navigationController!.viewControllers as [UIViewController]
    for aViewController:UIViewController in viewControllers {
        if aViewController.isKind(of: FromWhereYouWantToGoController.self) {
            _ = self.navigationController?.popToViewController(aViewController, animated: true)
        }
    }

这里FromWhereYouWantToGoController是目标控制器。希望能帮助到你。

Answer 11

您可以传递初始视图控制器（您想要返回的控制器），然后在最后一个视图中调用此行：

[self.navigationController popToViewController:yourInitialViewController animated:YES];

L，

Answer 12

快捷键4：

func popViewControllerss(popViews: Int, animated: Bool = true) {
    if self.navigationController!.viewControllers.count > popViews
    {
        let vc = self.navigationController!.viewControllers[self.navigationController!.viewControllers.count - popViews - 1]
         self.navigationController?.popToViewController(vc, animated: animated)
    }
}

然后使用此方法

self.popViewControllerss(popViews: 2)

Answer 13

我在这里没有看到这个答案。如果你只想弹出一些（不是一直到root），你可以通过self.navigationController.viewControllers迭代检查类类型，或者你有一个引用使用：

for (UIViewController *aViewController in self.navigationController.viewControllers) {
   if ([aViewController isKindOfClass:[SMThumbnailViewController class]]) {
      [self.navigationController popToViewController:aViewController animated:YES];
   }
}

Answer 14

您可以弹回根视图控制器

[self.navigationController popToRootViewControllerAnimated:YES];

或者，如果要弹出的视图不是第一个，则需要在上一个视图中再次弹出viewWillAppear

Answer 15

这是我用来返回X ViewControllers的一个小功能：

-(void)backMultiple:(id)data {
    int back = 2; //Default to go back 2 
    int count = [self.navigationController.viewControllers count];

    if(data[@"count"]) back = [data[@"count"] intValue];

    //If we want to go back more than those that actually exist, just go to the root
    if(back+1 > count) {
        [self.navigationController popToRootViewControllerAnimated:YES];
    }
    //Otherwise go back X ViewControllers 
    else {
        [self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:count-(back+1)] animated:YES];
    }
}

Answer 16

您可以使用UIViewControllers的堆栈。 1.获取堆栈中所有viewControllers的数组。 2.遍历整个数组并找到所需的viewController
通过匹配类类型。 3.弹出viewController。

func popToSpecificViewC
{
let viewControllers: [UIViewController] = self.navigationController!.viewControllers as [UIViewController];
        for viewController:UIViewController in viewControllers
        {
            if viewController.isKind(of: WelcomeViewC.self)
            {
                _ = self.navigationController?.popToViewController(viewController, animated: true)
            }
        }
}

Answer 17

Swift版本（Swift 1.2 / Xcode 6.3.1）弹出两次或更多次

 var viewControllers = self.navigationController?.viewControllers
 viewControllers?.removeLast()
 viewControllers?.removeLast()
 self.navigationController?.setViewControllers(viewControllers, animated: true)

或

 var viewControllers = self.navigationController?.viewControllers
 var viewsToPop = 2
 var end = (viewControllers?.count)!
 var start = end - viewsToPop
 viewControllers?.removeRange(Range<Int>(start: start, end: end))
 self.navigationController?.setViewControllers(viewControllers, animated: true)

Answer 18

使用简单的 UINavigationController扩展 ：

extension UINavigationController {
    func popViewControllers(_ count: Int) {
        guard viewControllers.count > count else { return }
        popToViewController(viewControllers[viewControllers.count - count - 1], animated: true)
    }
}

Answer 19

Swift 4.2

在您的navigationController?.viewControllers上，您可以在导航控制器上检查viewControllers，因此您只需要弹出想要的位置即可，

navigationController?.popToViewController(navigationController?.viewControllers[1], animated: true)

我要弹出的ViewController的位置是1。

如何从导航控制器一次弹出两个视图？

19 个答案:

的UINavigationController + popTwice.h

的UINavigationController + popTwice.m