Question

我想写三个并发例程，它们相互发送整数。现在，我已经实现了两个并发例程，它们相互发送整数。

package main
import "rand"

func Routine1(commands chan int, responses chan int) {
    for i := 0; i < 10; i++ {
        i := rand.Intn(100)
  commands <- i
  print(<-responses, " 1st\n");
}
close(commands)
}

func Routine2(commands chan int, responses chan int) {
for i := 0; i < 1000; i++ {
    x, open := <-commands
    if !open {
        return;
    }
     print(x , " 2nd\n");
    y := rand.Intn(100)
    responses <- y
}
}

func main() 
{
   commands := make(chan int)
   responses := make(chan int)
   go Routine1(commands, responses)
   Routine2(commands, responses)
}

但是，当我想添加另一个想要向上述例程发送和接收整数的例程时，它会出现错误，例如＆＃34; throw：所有goroutines都睡着了 - 死锁！＆＃34;。以下是我的代码：

package main
import "rand"

func Routine1(commands chan int, responses chan int, command chan int, response chan int ) {
for i := 0; i < 10; i++ {
    i := rand.Intn(100)
  commands <- i
  command <- i
  print(<-responses, " 12st\n");
  print(<-response, " 13st\n");
}
close(commands)
}

func Routine2(commands chan int, responses chan int) {
for i := 0; i < 1000; i++ {
    x, open := <-commands
    if !open {
        return;
    }
     print(x , " 2nd\n");
    y := rand.Intn(100)
    responses <- y
}
}

func Routine3(command chan int, response chan int) {
for i := 0; i < 1000; i++ {
    x, open := <-command
    if !open {
        return;
    }
     print(x , " 3nd\n");
    y := rand.Intn(100)
    response <- y
}
}

func main() {
   commands := make(chan int)
   responses := make(chan int)
   command := make(chan int)
   response := make(chan int)
   go Routine1(commands, responses,command, response )
   Routine2(commands, responses)
   Routine3(command, response)
}

任何人都可以帮助我，我的错误在哪里？任何人都可以帮助我，是否可以创建双向通道，或者是否可以为int，string等创建公共通道？

Answer 1

您尚未在command函数中声明response和main个变量。

func main() {
    commands := make(chan int)
    responses := make(chan int)
    go Routine1(commands, responses, command, response)
    Routine2(commands, responses)
    Routine3(command, response)
}

Go中的并发例程

1 个答案: