我有一个方法,我从onCreate(主线程)调用。在方法内部,我调用了另一个方法和一个重复调用相同方法的Runnable。这是它的外观,
public void start() {
try {
if (start == 0) {
playpause.setBackgroundDrawable(getResources().getDrawable(
R.drawable.play));
initialPoiPlayStatus = true;
playAudio();
}
if (play) {
if (mMediaPlayer != null && mMediaPlayer.isPlaying()) {
// for displaying view stub
poi = listOfPOI.get(j);
int pos = mMediaPlayer.getCurrentPosition();
int convSeconds = -1;
convSeconds = ((int) (pos) / 1000);
// displaying the you tube pop up based on the parsed value
// from the plist
youTube(convSeconds);
// call the method to change the image while the audio is
// playing
changeImage();
seek_bar.setProgress(current_position);
notification = new Runnable() {
public void run() {
start();
}
};
handler.postDelayed(notification, 1000);
} else {
if (j != (listOfPOI.size() - 1)) {
firstPlay = true;
initialPoiPlayStatus = true;
j++;
playAudio();
start();
// retrieve mascot info
if (isNetworkAvailable() == true) {
receiveResponse();
} else {
}
} else {
threadHandler.sendEmptyMessage(0);
}
}
}
} catch (Exception e) {
System.out.println(poi.getPlistPath());
e.printStackTrace();
}
}
现在在youtube中,
private void youTube(int convSeconds) {
frameLayout = (FrameLayout) findViewById(R.id.frameLayout);
youtubeWebView = (WebView) findViewById(R.id.youtubewebView);
try {
if (poi.getIsYoutubePresent().equals("true")) {
//mMediaPlayer.pause();
isNetworkAvailable();
if (isNetworkAvailable() == true) {
String startTimeyoutube = poi.getYoutubestartTime();
Integer youTubeStartTime = Integer
.parseInt(startTimeyoutube);
if (convSeconds == youTubeStartTime) {
if (frameLayout.getVisibility() == View.GONE) {
frameLayout.setVisibility(View.VISIBLE);
slideUp = AnimationUtils.loadAnimation(this,
R.anim.slide_up);
frameLayout.startAnimation(slideUp);
}
final String youTubeurl = poi.getLink();
WebSettings websets = youtubeWebView.getSettings();
websets.setJavaScriptEnabled(true);
registerForContextMenu(youtubeWebView);
youtubeWebView
.setWebViewClient(new ItemsWebViewClient());
youtubeWebView.loadUrl(youTubeurl);
youtubeWebView.getSettings().setLayoutAlgorithm(
LayoutAlgorithm.SINGLE_COLUMN);
firstPlay = false;
initialPoiPlayStatus = false;
paused = true;
play = false;
playpause.setBackgroundDrawable(getResources().getDrawable(
R.drawable.play));
if (mMediaPlayer.isPlaying()) {
mMediaPlayer.pause();
}
Button goBtn = (Button) findViewById(R.id.youtubeButton);
goBtn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View V) {
startActivity(new Intent(Intent.ACTION_VIEW,
Uri.parse(youTubeurl)));
}
});
ImageButton close = (ImageButton) findViewById(R.id.youtubecloseButton);
close.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
frameLayout.setVisibility(View.GONE);
if (!mMediaPlayer.isPlaying()) {
mMediaPlayer.start();
}
playpause.setBackgroundDrawable(getResources().getDrawable(
R.drawable.pause));
}
});
}
} else {
Toast.makeText(getApplicationContext(), "No network available", Toast.LENGTH_SHORT).show();
}
} else {
frameLayout.setVisibility(View.INVISIBLE);
}
} catch (Exception e) {
e.printStackTrace();
}
return;
}
此时,如果(convSeconds == youTubeStartTime){}成为真,我正在暂停音频,
if (mMediaPlayer.isPlaying()) {
mMediaPlayer.pause();
}
在此期间我还希望Runnable通知中的start()应该继续调用。但是,如果我暂停音频,则不会发生这种情况。在这种情况下,控制完全丢失。按下图像按钮关闭,我试图让音频再次像这样播放
if (!mMediaPlayer.isPlaying()) {
mMediaPlayer.start();
}
音频现在继续播放,但是滑块/搜索栏没有移动,因为通知中的start()没有被调用。
有人知道为什么会这样吗?
注意:如果我不让媒体播放器暂停,它可以正常工作。当我让音频暂停时,我得到了问题onky
答案 0 :(得分:0)
我最终解决了这个问题,它可能不是标准方式。但这对我有用。
我刚刚复制了
notification = new Runnable() {
public void run() {
start();
}
};
handler.postDelayed(notification, 1000);
我试图关闭图片按钮,即
ImageButton close = (ImageButton) findViewById(R.id.youtubecloseButton);
close.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
frameLayout.setVisibility(View.GONE);
if (!mMediaPlayer.isPlaying()) {
mMediaPlayer.start();
}
notification = new Runnable() {
public void run() {
start();
}
};
handler.postDelayed(notification, 1000);
}
});