Question

我很难合并一些哈希来获得我需要的结果。

哈希包含订单总价的细分，例如商品价格，税收和＆amp;发货，适用于订阅中的所有订单。我正在尝试动态执行此操作，因为并非所有订单都要征税，甚至是相同的税或运费。

这就是我所说的“我遇到的最坏情况”：

#First order - has charges for Canadian GST and HST
{:orderhdr_id=>17654122, :order_item_seq=>1, :order_item_amt_break_seq=>1, :order_item_break_type=>0, :local_amount=>8.16, :base_amount=>8.16, :orig_base_amount=>149, :tax_delivery=>0, :tax_active=>0}
{:orderhdr_id=>17654122, :order_item_seq=>1, :order_item_amt_break_seq=>2, :order_item_break_type=>1, :local_amount=>0.41, :base_amount=>0.41, :state=>"ON", :tax_type=>"GST", :tax_rate_category=>"STD", :orig_base_amount=>7.45, :tax_rate=>5, :tax_delivery=>0, :tax_active=>1, :tx_incl=>1}
{:orderhdr_id=>17654122, :order_item_seq=>1, :order_item_amt_break_seq=>3, :order_item_break_type=>1, :local_amount=>0.65, :base_amount=>0.65, :state=>"ON", :tax_type=>"HST", :tax_rate_category=>"STD", :orig_base_amount=>11.92, :tax_rate=>8, :tax_delivery=>0, :tax_active=>1, :tx_incl=>1}
#Second order - has only one charge for tax
{:orderhdr_id=>1815296, :order_item_seq=>1, :order_item_amt_break_seq=>1, :order_item_break_type=>0, :local_amount=>76.52, :base_amount=>76.52, :orig_base_amount=>99.95, :tax_delivery=>0, :tax_active=>0}
{:orderhdr_id=>1815296, :order_item_seq=>1, :order_item_amt_break_seq=>2, :order_item_break_type=>1, :local_amount=>4.59, :base_amount=>4.59, :orig_base_amount=>6, :tax_delivery=>0, :tax_active=>1}
#Third order - has charge for shipping
{:orderhdr_id=>6112412, :order_item_seq=>1, :order_item_amt_break_seq=>1, :order_item_break_type=>0, :local_amount=>21.34, :base_amount=>21.34, :orig_base_amount=>99.95, :tax_delivery=>0, :tax_active=>0}
{:orderhdr_id=>6112412, :order_item_seq=>1, :order_item_amt_break_seq=>2, :order_item_break_type=>2, :local_amount=>4.7, :base_amount=>4.7, :orig_base_amount=>22, :tax_delivery=>0, :tax_active=>0}

:order_item_break_type确定它是什么类型的费用，项目，税，运费。

如果:order_item_break_type为0或2，则从:base_amount中减去:orig_base_amount并将其添加到该中断类型的总计中。对于:order_item_break_type等于1，我需要总结:orig_base_amount和:base_amount，的差异，但我需要将不同的税分开。

所以这就是我应该为上述订单最终得到的结果：

:break_type = 0 | total = 242.88
:break_type = 1, :state = ON, :tax_type = GST, :tax_rate_category = STD | total = 7.04
:break_type = 1, :state = ON, :tax_type = HST, :tax_rate_category = STD | total = 11.27
:break_type = 1 | total = 1.41
:break_type = 2 | total = 17.30

我在名为@amounts的数组中有这些哈希值。

我有merge!，inject，shift这样的方法，而且还有更多方法，但不能把它放在一起。

Answer 1

这个怎么样？不过，我真的不知道你在做什么。

@amounts = [
#First order - has charges for Canadian GST and HST
{:orderhdr_id=>17654122, :order_item_seq=>1, :order_item_amt_break_seq=>1, :order_item_break_type=>0, :local_amount=>8.16, :base_amount=>8.16, :orig_base_amount=>149, :tax_delivery=>0, :tax_active=>0},
{:orderhdr_id=>17654122, :order_item_seq=>1, :order_item_amt_break_seq=>2, :order_item_break_type=>1, :local_amount=>0.41, :base_amount=>0.41, :state=>"ON", :tax_type=>"GST", :tax_rate_category=>"STD", :orig_base_amount=>7.45, :tax_rate=>5, :tax_delivery=>0, :tax_active=>1, :tx_incl=>1},
{:orderhdr_id=>17654122, :order_item_seq=>1, :order_item_amt_break_seq=>3, :order_item_break_type=>1, :local_amount=>0.65, :base_amount=>0.65, :state=>"ON", :tax_type=>"HST", :tax_rate_category=>"STD", :orig_base_amount=>11.92, :tax_rate=>8, :tax_delivery=>0, :tax_active=>1, :tx_incl=>1},
#Second order - has only one charge for tax
{:orderhdr_id=>1815296, :order_item_seq=>1, :order_item_amt_break_seq=>1, :order_item_break_type=>0, :local_amount=>76.52, :base_amount=>76.52, :orig_base_amount=>99.95, :tax_delivery=>0, :tax_active=>0},
{:orderhdr_id=>1815296, :order_item_seq=>1, :order_item_amt_break_seq=>2, :order_item_break_type=>1, :local_amount=>4.59, :base_amount=>4.59, :orig_base_amount=>6, :tax_delivery=>0, :tax_active=>1},
#Third order - has charge for shipping
{:orderhdr_id=>6112412, :order_item_seq=>1, :order_item_amt_break_seq=>1, :order_item_break_type=>0, :local_amount=>21.34, :base_amount=>21.34, :orig_base_amount=>99.95, :tax_delivery=>0, :tax_active=>0},
{:orderhdr_id=>6112412, :order_item_seq=>1, :order_item_amt_break_seq=>2, :order_item_break_type=>2, :local_amount=>4.7, :base_amount=>4.7, :orig_base_amount=>22, :tax_delivery=>0, :tax_active=>0},
]

@totals = Hash.new(0)

@amounts.group_by{|row| row[:order_item_break_type]}.each do |break_type, rows|

  rows.each do |row|

    key = [break_type, row[:tax_type]]
    @totals[key] += row[:orig_base_amount] - row[:base_amount]

  end
end

@totals
# => {[0, nil]=>242.88,
#     [1, "GST"]=>7.04,
#     [1, "HST"]=>11.27,
#     [1, nil]=>1.4100000000000001,
#     [2, nil]=>17.3}

如何有条件地合并哈希值并添加值？

1 个答案: