解密Python中使用PHP中的MCRYPT_RIJNDAEL_256加密的字符串

时间:2011-11-21 19:19:31

标签: php python encryption mcrypt

我在PHP中有一个函数加密文本,如下所示:

function encrypt($text)
{
    $Key = "MyKey";

    return trim(base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $Key, $text, MCRYPT_MODE_ECB, mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_256, MCRYPT_MODE_ECB), MCRYPT_RAND))));
}

如何在Python中解密这些值?

3 个答案:

答案 0 :(得分:16)

要解密这种加密形式,您需要获得Rijndael的版本。可以找到一个here。然后,您将需要模拟PHP Mcrypt模块中使用的键和文本填充。他们添加'\0'来填充文本并键入正确的大小。它们使用的是256位块大小,并且您使用的密钥使用的密钥大小为128(如果您给它一个更大的密钥,它可能会增加)。不幸的是,我链接的Python实现一次只编码一个块。我创建了python函数,用于模拟Python中的加密(用于测试)和解密

import rijndael
import base64

KEY_SIZE = 16
BLOCK_SIZE = 32

def encrypt(key, plaintext):
    padded_key = key.ljust(KEY_SIZE, '\0')
    padded_text = plaintext + (BLOCK_SIZE - len(plaintext) % BLOCK_SIZE) * '\0'

    # could also be one of
    #if len(plaintext) % BLOCK_SIZE != 0:
    #    padded_text = plaintext.ljust((len(plaintext) / BLOCK_SIZE) + 1 * BLOCKSIZE), '\0')
    # -OR-
    #padded_text = plaintext.ljust((len(plaintext) + (BLOCK_SIZE - len(plaintext) % BLOCK_SIZE)), '\0')

    r = rijndael.rijndael(padded_key, BLOCK_SIZE)

    ciphertext = ''
    for start in range(0, len(padded_text), BLOCK_SIZE):
        ciphertext += r.encrypt(padded_text[start:start+BLOCK_SIZE])

    encoded = base64.b64encode(ciphertext)

    return encoded


def decrypt(key, encoded):
    padded_key = key.ljust(KEY_SIZE, '\0')

    ciphertext = base64.b64decode(encoded)

    r = rijndael.rijndael(padded_key, BLOCK_SIZE)

    padded_text = ''
    for start in range(0, len(ciphertext), BLOCK_SIZE):
        padded_text += r.decrypt(ciphertext[start:start+BLOCK_SIZE])

    plaintext = padded_text.split('\x00', 1)[0]

    return plaintext

可以使用如下:

key = 'MyKey'
text = 'test'

encoded = encrypt(key, text)
print repr(encoded)
# prints 'I+KlvwIK2e690lPLDQMMUf5kfZmdZRIexYJp1SLWRJY='

decoded = decrypt(key, encoded)
print repr(decoded)
# prints 'test'

为了比较,这里是PHP的输出,文本相同:

$ php -a
Interactive shell

php > $key = 'MyKey';
php > $text = 'test';
php > $output = mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $key, $text, MCRYPT_MODE_ECB);
php > $encoded = base64_encode($output);
php > echo $encoded;
I+KlvwIK2e690lPLDQMMUf5kfZmdZRIexYJp1SLWRJY=

答案 1 :(得分:4)

如果您愿意在PHP端使用MCRYPT_RIJNDAEL_128而不是256,那么这很简单:

from Crypto.Cipher import AES
import base64
key="MyKey"

def decrypt(text)
    cipher=AES.new(key)
    return cipher.decrypt(base64.b64decode(text))

答案 2 :(得分:2)

虽然@ 101100的答案在当时是一个很好的答案,但它已不再可行。该引用现在是一个断开的链接,代码只能在较旧的Pythons(< 3)上运行。

相反,pprp project似乎很好地填补了空白。在Python 2或Python 3上,只需pip install pprp,然后:

import pprp
import base64

KEY_SIZE = 16
BLOCK_SIZE = 32


def encrypt(key, plaintext):
    key = key.encode('ascii')
    plaintext = plaintext.encode('utf-8')
    padded_key = key.ljust(KEY_SIZE, b'\0')

    sg = pprp.data_source_gen(plaintext, block_size=BLOCK_SIZE)
    eg = pprp.rjindael_encrypt_gen(padded_key, sg, block_size=BLOCK_SIZE)

    ciphertext = pprp.encrypt_sink(eg)

    encoded = base64.b64encode(ciphertext)

    return encoded.decode('ascii')


def decrypt(key, encoded):
    key = key.encode('ascii')
    padded_key = key.ljust(KEY_SIZE, b'\0')

    ciphertext = base64.b64decode(encoded.encode('ascii'))

    sg = pprp.data_source_gen(ciphertext, block_size=BLOCK_SIZE)
    dg = pprp.rjindael_decrypt_gen(padded_key, sg, block_size=BLOCK_SIZE)

    return pprp.decrypt_sink(dg).decode('utf-8')


key = 'MyKey'
text = 'test'

encoded = encrypt(key, text)
print(repr(encoded))
# prints 'ju0pt5Y63Vj4qiViL4VL83Wjgirq4QsGDkj+tDcNcrw='

decoded = decrypt(key, encoded)
print(repr(decoded))
# prints 'test'

我有点沮丧的是,密文与你在101100的回答中看到的不同。但是,我已经使用这种技术成功解密了在PHP中加密的数据,如OP中所述。