Question

我在尝试这项工作时遇到了一些麻烦。我有2个型号，User_Pro和Category。我阅读了关于kohana指南的关系文档，我理解我需要在User_Pro和Category模型上定义$_has_many关系，并使用belongs_to字段创建模型user_pro_categories。

User_Pro型号：

protected $_has_many = array(
    'categories' => array(
        'model'   => 'TM_Category',
        'through' => 'user_pro_categories',
            'foreign_key' => 'id_user_pro',
    ),
);

类别模型：

protected $_has_many = array(
    'users_pro' => array(
        'model'   => 'TM_User_Pro',
        'through' => 'user_pro_categories',
        'foreign_key' => 'id_category',
    ),
);

user_pro_categories型号：

    protected $_belongs_to = array(
        'user_pro' => array(
            'model'       => 'TM_User_Pro',
            'foreign_key' => 'id_user_pro',
        ),
        'category' => array(
            'model'       => 'TM_Category',
            'foreign_key' => 'id_category',
        ),
);

我得到的错误是：

Database_Exception [ 1054 ]: Unknown column 'tm3_user_pro_categories.category_id' in 
'on clause' [ SELECT `tm3_tm_category`.* FROM `tm3_categories` AS `tm3_tm_category` JOIN 
`tm3_user_pro_categories` ON (`tm3_user_pro_categories`.`category_id` = `tm3_tm_category`.`id_category`) 
WHERE `tm3_user_pro_categories`.`id_user_pro` = '2' ]

它就像它不关心我定义的fk，它想要使用后缀的东西......任何想法？

Answer 1

以下示例可让您快速了解Kohana ORM的工作原理。并希望它对其他人也有帮助。

学生模特

<?php defined('SYSPATH') or die('No direct script access.');

class Model_Student extends ORM {

    protected $_primary_key = 'idstudent'; // take a look

    protected $_has_many = array(
        'courses'=> array(
            'model' => 'course',                // Course model
            'through' => 'students_courses',    // many-to-may through
            'far_key' => 'id_for_course',       // "column name" relating to the Course Model in "students_courses" table  
            'foreign_key' => 'id_for_student'   // "column name" relating to the Student Model in "students_courses" table
        ),
    );

}

课程模型

<?php defined('SYSPATH') or die('No direct script access.');

class Model_Course extends ORM {

    protected $_primary_key = 'idcourse'; // take a look

    protected $_has_many = array(
        'students'=> array(
            'model'         => 'student',
            'far_key'       => 'id_for_student',
            'through'       => 'students_courses',
            'foreign_key'   => 'id_for_course'
        ),
    );

}

SQL脚本

CREATE TABLE IF NOT EXISTS `students` (
  `idstudent` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `name` varchar(45) DEFAULT NULL,
  PRIMARY KEY (`idstudent`)
) ENGINE=MyISAM;

INSERT INTO `students` (`idstudent`, `name`) VALUES
(1, 's1'),
(2, 's2');
/* column idcourse and PR idcourseS ? */
CREATE TABLE IF NOT EXISTS `courses` (
  `idcourse` int(11) NOT NULL,
  `name` varchar(45) DEFAULT NULL,
  PRIMARY KEY (`idcourse`)
) ENGINE=MyISAM;

INSERT INTO `courses` (`idcourse`, `name`) VALUES
(1, 'c1'),
(2, 'c2'),
(3, 'c3');

CREATE TABLE IF NOT EXISTS `students_courses` (
  `id_for_student` int(10) unsigned NOT NULL,
  `id_for_course` int(10) unsigned NOT NULL
) ENGINE=MyISAM;

INSERT INTO `students_courses` (`id_for_student`, `id_for_course`) VALUES
(1, 1),
(1, 3);

    $student = new Model_Student(1);
    $courses = $student->courses->find_all();
    echo Debug::vars($courses);
    foreach($courses as $course) {
        echo Debug::vars($course->object());
    }

运行上面的代码将创建以下SQL查询。

SELECT `course`.* FROM `courses` AS `course` JOIN `students_courses` ON (`students_courses`.`id_for_course` = `course`.`idcourse`) WHERE `students_courses`.`id_for_student` = '1'

Answer 2

您无需为多对多关系创建数据透视表的模型。只需在两个模型中定义through选项，确保您的主键/外键遵循Kohana惯例，然后您就可以开始了。以下来自Kohana ORM用户和角色模型的示例：

class Model_User
{
    protected $_has_many = array(
        'roles' => array('model' => 'role', 'through' => 'roles_users'),
    );
}

class Model_Role 
{
    protected $_has_many = array(
                 'users' => array('model' => 'user', 'through' => 'roles_users')
        );
}

关于kohana的多对多关系3.2

2 个答案: