Question

执行我的Android应用程序时出现此错误：

Host is unresolved: api.twitter.com:80
Relevant discussions can be on the Internet at:
http://www.google.co.jp/search?q=10f5ada3 or
http://www.google.co.jp/search?q=dceba048
TwitterException{exceptionCode=[10f5ada3-dceba048 10f5ada3-dceba01e], statusCode=-1, retryAfter=-1, rateLimitStatus=null, featureSpecificRateLimitStatus=null, version=2.2.5}

虽然我已经设置了适当的权限..这是我的代码：

的AndroidManifest.xml

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.abc"
    android:versionCode="1"
    android:versionName="1.0" >

    <uses-sdk android:minSdkVersion="8" />
    <uses-permission android:name="android.permission.INTERNET" />

    <application
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name" >

            <activity
            android:label="test1"
            android:name=".A1Activity" 
            android:launchMode="singleTask">
            <intent-filter >
                <action android:name="android.intent.action.MAIN" />
                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>

            <intent-filter>
                           <action android:name="android.intent.action.VIEW" />
                           <category android:name="android.intent.category.DEFAULT" />
                           <category android:name="android.intent.category.BROWSABLE" />
                           <data android:scheme="twitterapp" android:host="callback" />
            </intent-filter>
        </activity>

     <activity class=".screen2" android:label="test2" android:name=".screen2">
      </activity>
    </application>

</manifest>

我的文件代码是：

public class A1Activity extends Activity {

         private static final String PREF_ACCESS_TOKEN = "accessToken"; // Called when the activity is first created.      
         private static final String PREF_ACCESS_TOKEN_SECRET = "accessTokenSecret";// Name to store the users access token secret   
         public final static String CONSUMER_KEY = "abc"; // "your key here";
         public final static String CONSUMER_SECRET = "def"; // "your secret key here";     
         private static final String CALLBACK_URL = "twitterapp://callback";// The url that Twitter will redirect to after a user log
         private SharedPreferences mPrefs;     // Preferences to store a logged in users credentials 
         private Twitter mTwitter;// = new TwitterFactory().getInstance(); 
         private RequestToken mReqToken;/** The request token signifies the unique ID of the request you are sending to twitter  */
         public int returnFlag=0;

        @Override
        public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.main);

                mPrefs = getSharedPreferences("twitterPrefs", MODE_PRIVATE);            
                mTwitter = new TwitterFactory().getInstance();       
                mTwitter.setOAuthConsumer(CONSUMER_KEY, CONSUMER_SECRET);
                Button mLoginButton = (Button) findViewById(R.id.login_button);
                mLoginButton.setOnClickListener(new View.OnClickListener() {
                    public void onClick(View v) {
                        System.out.println("1");
                        loginNewUser();
                        System.out.println("7.saveAccessToken ");
                        //Intent screenEnterZip = new Intent(A1Activity.this, screen2.class);
                        //startActivity(screenEnterZip);// Perform action on click                
                        }
                    });
                }


        public void loginNewUser() {        
            try { 
                    System.out.println("2");
                    mReqToken = mTwitter.getOAuthRequestToken(CALLBACK_URL);
                    System.out.println("2.1");
                    WebView twitterSite = new WebView(this);
                    System.out.println("2.2");
                    twitterSite.loadUrl(mReqToken.getAuthenticationURL());
                    System.out.println("2.3");
                    setContentView(twitterSite);                
                    //Status status = mTwitter.updateStatus("My First Tweet ... ");                
                    //System.out.println("Successfully updated the status to [" + status.getText() + "].");                
                    System.out.println("1. loginNewUser Completes ");
                }
            catch (TwitterException e) {
                System.out.println("ExceptioniZ "+e);
                Toast.makeText(this, "Twitter Login error, try again later", Toast.LENGTH_SHORT).show();
            }
        }

应用程序在模拟器中打开，屏幕显示登录按钮。但是在登录按钮上单击它会在应用程序几小时前工作时抛出常规错误...
任何人都可以提出可能存在问题的原因......？

Answer 1

您的模拟器中可能没有互联网连接。

在模拟器中打开浏览器并输入“http://api.twitter.com”。这可能行不通。在你的本地电脑上也应该这样做。

主持人尚未解决：api.twitter.com：80

1 个答案: