Question

我想扩展DataGridView以添加第二个ContextMenu，用于选择gird中可见的列。右键单击列的标题将显示新的ContextMenu。

我很难获得正确的水平位置来显示上下文菜单。我怎么能纠正这个？

public partial class Form1 : Form
{
    DataGridView dataGrid;
    ContextMenuStrip contextMenuStrip;        

    public Form1()
    {
        InitializeComponent();

        dataGrid = new DataGridView();
        Controls.Add(dataGrid);
        dataGrid.Dock = System.Windows.Forms.DockStyle.Fill;
        dataGrid.ColumnHeaderMouseClick += new System.Windows.Forms.DataGridViewCellMouseEventHandler(ColumnHeaderMouseClick);
        dataGrid.DataSource = new Dictionary<string, string>().ToList();

        contextMenuStrip = new ContextMenuStrip();
        contextMenuStrip.Items.Add("foo");
        contextMenuStrip.Items.Add("bar");
    }

    private void ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e)
    {
        if (e.Button == System.Windows.Forms.MouseButtons.Right)
        {
            contextMenuStrip.Show(PointToScreen(e.Location));
        }
    }
}

Answer 1

这是一种非常简单的方法，可以在右键单击上方显示上下文菜单。

处理事件 ColumnHeaderMouseClick

private void grid_ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e) {
  if (e.Button == System.Windows.Forms.MouseButtons.Right) {
    contextMenuHeader.Show(Cursor.Position);
  }
}

contextMenuHeader是ContextMenuStrip，可以在Designer视图中或在运行时定义。

Answer 2

要获取鼠标光标的坐标，您可以执行此操作。

ContextMenu.Show(this, myDataGridView.PointToClient(Cursor.Position));

Answer 3

您是否尝试过使用接受控件和位置的Show重载？

例如：

contextMenuStrip.Show(dataGrid, e.Location);

编辑：完整示例

public partial class Form1 : Form
{
    DataGridView dataGrid;
    ContextMenuStrip contextMenuStrip;        

    public Form1()
    {
        InitializeComponent();

        dataGrid = new DataGridView();
        Controls.Add(dataGrid);
        dataGrid.Dock = System.Windows.Forms.DockStyle.Fill;
        dataGrid.MouseDown += MouseDown;
        dataGrid.DataSource = new Dictionary<string, string>().ToList();

        contextMenuStrip = new ContextMenuStrip();
        contextMenuStrip.Items.Add("foo");
        contextMenuStrip.Items.Add("bar");
    }

    private void MouseDown(object sender, MouseEventArgs e)
    {
        if (e.Button == System.Windows.Forms.MouseButtons.Right)
        {
            if (dataGrid.HitTest(e.X, e.Y).Type == DataGridViewHitTestType.ColumnHeader)
            {
                contextMenuStrip.Show(dataGrid, e.Location);
            }
        }
    }
}

Answer 4

e.Location不会在正确的坐标处显示弹出菜单，而只是使用MousePosition属性，如下所示：

ContextMenuStrip.Show(MousePosition)

或者，明确地

ContextMenuStrip.Show(Control.MousePosition)

Answer 5

返回的位置是相对于单元格的。所以我们必须添加那个偏移量。

    private void grdView_CellMouseClick(object sender, DataGridViewCellMouseEventArgs e)
    {
        if (e.Button == MouseButtons.Right)
        {
            var pos = ((DataGridView)sender).GetCellDisplayRectangle(e.ColumnIndex, 
            e.RowIndex, false).Location;
            pos.X += e.X;
            pos.Y += e.Y;
            contextMenuStrip.Show((DataGridView)sender,pos);
        }
    }

Answer 6

我出错的地方是DataGridViewCellMouseEventArgs返回鼠标在列标题中单击的位置/ x，y。相反，我需要在网格的MouseDown事件中使用HitTest来对列标题进行点击，然后将点击的位置从网格坐标转换为屏幕坐标。

public partial class Form1 : Form { DataGridView dataGrid; ContextMenuStrip contextMenuStrip; public Form1() { InitializeComponent(); dataGrid = new DataGridView(); Controls.Add(dataGrid); dataGrid.Dock = System.Windows.Forms.DockStyle.Fill; //dataGrid.ColumnHeaderMouseClick += ColumnHeaderMouseClick; dataGrid.MouseDown += MouseDown; dataGrid.DataSource = new Dictionary<string, string>().ToList(); contextMenuStrip = new ContextMenuStrip(); contextMenuStrip.Items.Add("foo"); contextMenuStrip.Items.Add("bar"); } private void ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e) { if (e.Button == System.Windows.Forms.MouseButtons.Right) { contextMenuStrip.Show(PointToScreen(e.Location)); } } private void MouseDown(object sender, MouseEventArgs e) { if (e.Button == System.Windows.Forms.MouseButtons.Right) { if (dataGrid.HitTest(e.X, e.Y).Type == DataGridViewHitTestType.ColumnHeader) { contextMenuStrip.Show(dataGrid.PointToScreen(e.Location)); } } } }

Answer 7

两次调用Show将为您提供光标的确切位置。此答案适用于无法通过上述所有答案获得结果的人。

private void MouseDown(object sender, MouseEventArgs e)
{
    if (e.Button == System.Windows.Forms.MouseButtons.Right)
    {
        contextMenuStrip.Show(dataGrid, e.Location));
        contextMenuStrip.Show(Cursor.Position);
    }
}

Answer 8

最后这对我有用。

ContextMenu.Show(myDataGridView, myDataGridView.PointToClient(Cursor.Position));

Answer 9

你几乎是对的。您只需将PointToScreen方法应用于调用控件：

private void ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e)
{
    if (e.Button == System.Windows.Forms.MouseButtons.Right)
    {
        contextMenuStrip.Show(((DataGridView)sender).PointToScreen(e.Location));
    }
}

我认为这是最优雅的解决方案，因为它只使用ColumnHeaderMouseClick个参数，而不是Cursor.Position。

当我右键单击DataGridView的列标题时，如何正确定位上下文菜单？

9 个答案: