Question

这是该计划的输出：

*** start of 276 2D Arrays_03.cpp program ***

Number    Count     Total
   1        3         3
   2        6         9
   3       15        24
   4        6        30
   5        9        39

*** end of 276 2D Arrays_03.cpp program ***

这是代码：

#include <iostream>
#include <string>
#include <iomanip>
using namespace std;

const int COLUMN_SIZE = 13;

int main(void)
{
    const int ROW_SIZE = 3;
    const int COUNT_SIZE = 5;

    void countValues(const int[][COLUMN_SIZE], const int, int[]);
    void display(const int [], const int);

    int numbers[ROW_SIZE][COLUMN_SIZE] = {{1, 3, 4, 5, 3, 2, 3, 5, 3, 4, 5, 3, 2},
                                    {2, 1, 3, 4, 5, 3, 2, 3, 5, 3, 4, 5, 3},
                {3, 4, 5, 3, 2, 1, 3, 4, 5, 3, 2, 3, 5}};

    int counts[COUNT_SIZE] = {0};
    string choice;

    cout << "*** start of 276 2D Arrays_03.cpp program ***" << endl;
    cout << endl;

    countValues(numbers, ROW_SIZE, counts);

    display(counts, COUNT_SIZE);

    cout << endl;
    cout << endl;
    cout << "*** end of 276 2D Arrays_03.cpp program ***" << endl << endl;

    cin.get();
    return 0;
}   // end main()

这是我需要计算每个值的函数。我知道如何对行和列进行求和，但我不太确定代码只是为了自己计算值。

void countValues(const int numbers[][COLUMN_SIZE], const int ROW_SIZE, int counts[])

这是我到目前为止所做的。

{
 for (int index = 0; index < ROW_SIZE; index++)
  counts[index];
{

Answer 1

我不会为你做功课，但也许这会对你有所帮助：

你有一个数组“计数”...
该数组中每个元素的索引对应于您的值...

如果您对值进行检测，则可以轻松找到当前值的相应数组元素

请记住，数组从0开始计数，但是您的值从1开始计数

Answer 2

好吧，这似乎是你的功课，看起来不值得尝试如何编写好的代码，而你处于这个级别，所以我只是发布核心代码：

#include <iostream>
#include <string>
#include <iomanip>
using namespace std;

// if you declare these here, you don't need to pass ROW_SIZE as a parameter
const int COLUMN_SIZE = 13;
const int ROW_SIZE = 3;
const int COUNT_SIZE = 5;

// you should declare functions in the global scope
void countValues(const int[][COLUMN_SIZE], int[]);
void display(const int [], const int);


int main(void)
{    
    int numbers[ROW_SIZE][COLUMN_SIZE] = {{1, 3, 4, 5, 3, 2, 3, 5, 3, 4, 5, 3, 2},
                                    {2, 1, 3, 4, 5, 3, 2, 3, 5, 3, 4, 5, 3},
                {3, 4, 5, 3, 2, 1, 3, 4, 5, 3, 2, 3, 5}};

    int counts[COUNT_SIZE] = {0, 0, 0, 0, 0}; // <-- you should init all the five elements since COUNT_SIZE is 5 in your code
    string choice;

    cout << "*** start of 276 2D Arrays_03.cpp program ***" << endl;
    cout << endl;

    countValues(numbers, counts);

    display(counts, COUNT_SIZE);

    cout << endl;
    cout << endl;
    cout << "*** end of 276 2D Arrays_03.cpp program ***" << endl << endl;

    cin.get();
    return 0;
}   // end main()

void countValues(const int numbers[][COLUMN_SIZE], int counts[])
{
    for (int i = 0; i < ROWSIZE; ++ i)
        for (int j = 0; j < COLUMN_SIZE; ++ j)
        {
            ++ counts[numbers[i][j] + 1];
        }
}

顺便说一下，我为你写了一些评论，所以你可以删除你最后的作品

我如何获得一个数组来计算有多少数字而不是计算每个数字的值？

2 个答案: