ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
String id = cur.getString(
cur.getColumnIndex(ContactsContract.Contacts._ID));
String name = cur.getString(
cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (name.equals(selected) && Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
Cursor pCur = cr.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " =?", new String[] {
id
}, null);
finalsend = ContactsContract.CommonDataKinds.Phone.NUMBER;
while (pCur.moveToNext()) {
}
pCur.close();
}
代码应该通过联系人来查找匹配“选定”变量的代码,该变量似乎工作正常但是它应该切换到ContactsContract.CommonDataKinds.Phone.CONTENT_URI
并通过匹配ID来找到相同的联系人并告诉我为该联系人保存的电话号码。
每次返回“Data1”时,我做错了什么?这可能是一个愚蠢的错误,但任何帮助都表示赞赏。
答案 0 :(得分:0)
以下代码段对我有用:
String id , name;
ContentResolver cr = getContentResolver();
String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, sortOrder);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
name = cur.getString( cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
Log.i(tag, "Id is "+ id+"\t Name is"+name);
if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0){
Cursor pCur = cr.query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?", new String[]{id}, null);
while (pCur.moveToNext()) {
// Do something with phones
int phNumber = pCur.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER);
String phn = pCur.getString(phNumber);
Log.i("phn number", phn);
}
pCur.close();
}
}
}