我在使用Allocatable数组时遇到了麻烦。
我必须将文件中的所有信息复制到可分配的数组中。 该文件是这样的:
3
3 5
2 1
4 0
3是分数 其他六个数字以(x,y)形式显示图表上的点。 所以(3,5),(2,1),(4,0)是要点。 但我有问题将这些数字作为一对。
我尝试编码,这是我的编码:
PROGRAM practice
IMPLICIT NONE
INTEGER :: astat, ioStatus
INTEGER :: x, y
INTEGER :: num, code1, code2, code3, code4, code5, code6
! num shows number of location. in this case 3
! code 1 to 6 shows x and y variable. and code1 and 2 have to be paired.
! as well as this, code 3 and 4, code 5 and 6 have to be paired
! Declare TYPE
! set 1 to 3 show pair of (x, y)
TYPE Location
INTEGER :: set1, set2, set3
INTEGER :: num_locations
END TYPE
! Array ()
! for number of locations to visit
TYPE(Location), DIMENSION(:) :: numLocationArray(1000)
! allocatable array
! For locations
TYPE(Location), DIMENSION(:, :) :: LocationArray
ALLOCATABLE :: LocationArray
! allocate LocationArray
ALLOCATE(LocationArray(x, y), STAT = astat)
IF (astat < 0) STOP "allocate failed"
! open input file to copy info into array
OPEN (UNIT = 10, File ="input.txt", STATUS = "OLD", ACTION = "READ", &
IOSTAT = ioStatus)
IF (ioStatus < 0) STOP "open failed"
! format of the file
100 FORMAT (I1, /, 2I2, /, 2I2, / 2I2)
! Do loop to set table
DO x = 0, size(LocationArray), 1
READ (UNIT = 10, FMT = 100, IOSTAT = ioStatus) num, code1, code2, &
code3, code4, code5, code6
! check whether program read file correctly (option)
PRINT *, num, code1, code2, code3, code4, code5, code6
IF (x == code1) THEN
DO y = 0, size(LocationArray), 1
IF (y == code2) THEN
LocationArray%set1 = LocationArray(x, y)
! check whether copied correctly
PRINT *, LocationArray(x, y)
PRINT *, LocationArray%set1
END IF
END DO
END IF
END DO
! ==============
! execution part
! ==============
! instructions:
! use pointer to do excecution
! read allocatable array above
! do excecution (distance) ** do not forget to go back to the original place (0,0)
! ** do not forget to try every single possible way
! when get total distance, do distance times 2 and figure out cost
! print all info (cost, distance, and steps)
! (example of output)
! The minimum cost is 36
! The distance travelled is 18
! Step 1: Start at ( 0, 0)
! Step 2: Goes to ( 2, 1)
! Step 3: Goes to ( 3, 5)
! Step 4: Goes to ( 4, 0)
! Step 5: Ends at ( 0, 0)
END PROGRAM
这个程序不起作用......我有一个错误:
LocationArray%set1 = LocationArray(x, y)
Error: Can't convert TYPE(location) to INTEGER(4) at (1)
我厌倦了解这个错误,但我做不到 有没有人对我的编码提出任何建议或建议?
原谅我的英语,我是日本人。
如果有人对我的问题有疑问(我的意思是需要更多解释),请告诉我。
谢谢。 UKA
答案 0 :(得分:1)
在类型Location
的定义中,您已经说过set1,set2和set3是整数变量,然后您尝试为其分配一个数组。我认为你想要的是因为这些是对,所以set1,set2和set3是一个大小为2的整数数组。
如果您将Location
类型更改为:
TYPE Location
INTEGER, DIMENSION(2) :: set1, set2, set3
INTEGER :: num_locations
END TYPE
读取数据的循环对我来说也没有意义。我想我会把它写成(注意Fortran中的数组默认是从1开始的,而不是像C中那样从零开始):
DO x = 1, size(numLocationArray), 1
READ (UNIT = 10, FMT = 100, IOSTAT = ioStatus) num, code1, code2, &
code3, code4, code5, code6
! check whether program read file correctly (option)
PRINT *, num, code1, code2, code3, code4, code5, code6
numLocationArray(x)%num_locations = num
numLocationArray(x)%set1(0) = code1
numLocationArray(x)%set1(1) = code2
numLocationArray(x)%set2(0) = code3
numLocationArray(x)%set2(1) = code4
numLocationArray(x)%set3(0) = code5
numLocationArray(x)%set3(1) = code6
END DO
您显然需要做一些事情来检测和处理文件结束条件。
如果位置的数量确实是可变的,那么您需要执行以下操作:
TYPE Coordinate
INTEGER :: x
INTEGER :: y
END TYPE
TYPE Locations
TYPE(Coordinate), DIMENSION(:), ALLOCATABLE :: location
INTEGER :: num_locations
END TYPE
TYPE(Location), DIMENSION(:) :: numLocationArray(1000)
! open input file to copy info into array
OPEN (UNIT = 10, File ="input.txt", STATUS = "OLD", ACTION = "READ", &
IOSTAT = ioStatus)
IF (ioStatus < 0) STOP "open failed"
! format of the file
100 FORMAT (I1 )
200 FORMAT (2I2)
DO n = 1, size(numLocationArray), 1
READ (UNIT = 10, FMT = 100, IOSTAT = iostatus) num
numLocationArray(n)%num_locations = num
ALLOCATE (numLocationArray(n)%locations(num), STAT = astat)
if (astat < 0) STOP 'allocate failed'
DO l = 1, num, 1
READ (UNIT = 10, FMT = 200, IOSTAT = iostatus) x, y
numLocationArray(n)%locations(l)%x = x
numLocationArray(n)%locations(l)%y = y
END DO
END DO
答案 1 :(得分:0)
看起来你试图给一个整数值两个整数。这就像你试图做的那样=(或var = 5,5)。