Question

我在Oracle上有两个表。说：

table1:
id    varchar2,
name  varchar2,
phone number,
age   number,
a     varchar2,
b     varchar2,
c     varchar2

table2:
z varchar2,
a varchar2,
b varchar2,
c varchar2

我应该得到table 1的所有结果 a上有b，c，table 2的组合。

我该怎么办？

Answer 1

听起来你想要NOT EXISTS

SELECT *
  FROM table1 t1
 WHERE NOT EXISTS (
    SELECT 1
      FROM table2 t2
     WHERE t1.a = t2.a
       AND t1.b = t2.b
       AND t1.c = t2.c )

Answer 2

不确定你是否想要这个：

SELECT *
FROM table1 t1
LEFT JOIN table2 t2 ON t1.a=t2.a AND t1.b=t2.b AND t1.c=t2.c
WHERE t2.z IS NULL

Answer 3

您可以使用存在子句。

Select *
from table1 t1
where not exists
 (select * from table2 t2
  where t1.a = t2.a
  and t1.b = t2.b
  and t1.c = t2.c)

从另一个表中没有该组合的表中获取所有结果

3 个答案: