的信息: 有一个组对象。可以邀请用户加入群组。有两种类型的组邀请:外部和内部。所有邀请都使用鉴别器存储在单个表中。组对象仅了解内部邀请。
问题在Invite表中有两条记录。一个用于内部,一个用于外部。如果我加载该组,我将看到两个邀请甚至集合都是InternalInvite类型。
SELECT internalin0_.Group_id as Group3_1_,
internalin0_.Id as Id1_,
internalin0_.Id as Id0_0_,
internalin0_.Group_id as Group3_0_0_,
internalin0_.User_id as User5_0_0_
FROM [AbstractInvite] internalin0_ 内部inin0_.Group_id ='be60b160-659e-4157-b033-9f9e00e346c7'
当我将ISet集合类型更改为AbstractInvite时,它将加载具有正确类型的所有邀请。
问题如何将集合属性仅映射到InternalInvites?
我会尽量尽量减少代码。
群组映射:
public class Group
{
public Group()
{
InternalInvitations = new HashedSet<InternalInvite>();
}
public virtual Guid Id { get; set; }
public virtual ISet<InternalInvite> InternalInvitations { get; set; }
}
public class GroupMap : ClassMap<Group>
{
public GroupMap()
{
Id(x => x.Id);
HasMany(x => x.InternalInvitations).Inverse();
}
}
外部和内部邀请+映射:
public abstract class AbstractInvite
{
public virtual Guid Id { get; set; }
public virtual Group Group { get; set; }
}
public class ExternalInvite : AbstractInvite
{
public virtual string Name { get; set; }
}
public class InternalInvite : AbstractInvite
{
public virtual User User { get; set; }
}
public class AbstractInviteMap : ClassMap<AbstractInvite>
{
public AbstractInviteMap()
{
Id(x => x.Id);
References(x => x.Group);
DiscriminateSubClassesOnColumn("type");
}
}
public class ExternalInviteMap : SubclassMap<ExternalInvite>
{
public ExternalInviteMap()
{
Map(x => x.Name);
}
}
public class InternalInviteMap : SubclassMap<InternalInvite>
{
public InternalInviteMap()
{
References(x => x.User);
}
}
答案 0 :(得分:2)
我会回答自己。
我能够通过以下代码实现我的目标:
public class AbstractInviteMap : ClassMap<AbstractInvite>
{
public AbstractInviteMap()
{
Id(x => x.Id);
References(x => x.Group);
DiscriminateSubClassesOnColumn("type").AlwaysSelectWithValue();
}
}
参考:Discriminator in NHibernate documentation. Focus on 'force' option.
答案 1 :(得分:1)
quickfix / workaround将是
HasMany(x => x.InternalInvitations).Inverse().Where("type = 'Namespace.InternalInviteMap'");