Question

我有一个SQL查询：

$cond = "";
    if($cid >0 )
    {
        $quali = $this->getCandidatesQualification($cid);

        $cond = "WHERE emp_qualification LIKE '%$quali%'";
    }

    $sql = "SELECT
            emp_job_id,emp_job_profie,emp_qualification,emp_experience
        FROM
            tbl_emp_data
            $cond
        ORDER BY job_add_date DESC LIMIT 0,10   
    ";
    $res = $this->db->returnArrayOfObject($sql,$pgin = 'no', $odr='no');

如果emp_qualification字段等于any_graduate，我想要的是我想要为候选人选择所有工作，即使他的资格是BA。

Answer 1

所以将WHERE子句修改为

WHERE emp_qualification LIKE '%$quali%' 
OR emp_qualification = 'any_graduate'

Answer 2

$cond = '';
if($cid >0 ) {
    if ($this->getCandidatesQualification($cid) != 'any_graduate') {
        $cond = "WHERE emp_qualification LIKE '%{$this->getCandidatesQualification($cid)}%'";
    }
}

简化，试试这个

为查询中的字段设置条件

2 个答案: