Question

我需要在数据库表中找到具有大写值字段的行。

E.g.: select * from Cust where Surname like 'COnTAiNS UpPERcASE VaLUeS'

任何帮助都将不胜感激。

AJ

Answer 1

您可以使用以下方式进行二进制比较：

select *
from Cust
where cast(Surname as varbinary(120)) != cast(lower(Surname) as varbinary(120))

Answer 2

另一种方式

SELECT *
FROM Cust
WHERE Surname NOT LIKE '%[^A-Z]%' COLLATE Latin1_General_BIN

Answer 3

你可以这样做：

SELECT 
 CASE WHEN BINARY_CHECKSUM('yourStriNg') = BINARY_CHECKSUM(LOWER('yourStriNg')) 
     THEN 0 
     ELSE 1 
 END

...

其余的SQL语句

Answer 4

尝试从给定的字符串值中仅提取大写字母：

Declare @Val Varchar(100)
Set @Val='MicrosoftAsp.NeT4You'

--Return Val
Declare @RetCapWord varchar(100)
Set @RetCapWord=''

;WITH CTE AS
(
    Select @Val As oldVal,1 As TotalLen,SUBSTRING(@Val,1,1) As newVal,
    ASCII(SUBSTRING(@Val,1,1)) As AsciVal

    UNION ALL

    Select oldVal,TotalLen+1 As TotalLen,
    substring(@Val,TotalLen+1,1) As newVal,
    ASCII(SUBSTRING(@Val,TotalLen+1,1)) As AsciVal
    From CTE
    where CTE.TotalLen<=LEN(@Val)
)
Select @RetCapWord=@RetCapWord+newVal
From CTE
Inner Join master..spt_values as m on CTE.AsciVal=m.number and CTE.AsciVal between 65 and 90

Select @RetCapWord

Answer 5

这对我有用

SELECT * FROM agents 
WHERE  email REGEXP BINARY  '[A-Z]'

Answer 6

这可能过于简单，但适用于我的用例：

SELECT *
FROM Cust
WHERE Surname != LOWER(Surname)

在SQL Server数据库字段中找到大写字符

6 个答案: