离开加入学说2

时间:2011-11-16 21:34:59

标签: mysql sql doctrine-orm

我有两个简单的实体:

  My\Entity\Coupon:
    type: entity
    table: coupon
    id:
      id:
        type: integer
        generator:
          strategy: AUTO
    fields:
      name:
        type: string
        length: 255
            nullable: false
      value:
         type: integer
         default: 0

    My\Entity\CouponUsers:
      type: entity
      table: coupon_users
      id:
        id:
          type: integer
          length: 11
          nullable: false
          generator:
            strategy: AUTO
      fields:
            coupon_id:
          type: integer
          length: 11
          nullable: false
        user_id:
          type: integer

现在,我想显示使用过的优惠券的简单统计数据 在phpMyAdmin中运行此SQL:

SELECT c.name, count( * ) AS mycount
FROM coupon c
LEFT JOIN coupon_users u ON c.id = u.coupon_id
GROUP BY c.id
ORDER BY mycount DESC

按预期正常工作,返回:

name1    54
name2    120

然后,我尝试从Doctrine 2中做同样的事情:

$queryBuilder = $this->_em->createQueryBuilder()
    ->select('c.name, COUNT(*) as co')
    ->from('My\Entity\Coupon', 'c')
    ->leftJoin('My\Entity\CouponUsers', 'u',
        \Doctrine\ORM\Query\Expr\Join::ON, 'c.id = u.coupon_id')
    ->where('u.coupon_id = c.id')
    ->groupBy('c.id');

$dql = $queryBuilder->getDQL();
var_dump($dql);

SELECT c.name,
   COUNT(*) as co 
FROM My\Entity\Coupon c
LEFT JOIN My\Entity\CouponUsers u
ON c.id = u.coupon_id
WHERE u.coupon_id = c.id
GROUP BY c.id

到目前为止,这么好。但是当我这样做时:

$queryBuilder->getQuery()->getResult();

我收到错误:

[Syntax Error] line 0, col 88: Error: Expected Doctrine\ORM\Query\Lexer::T_DOT, got 'u'

怎么了?我该如何解决这个问题?

1 个答案:

答案 0 :(得分:6)

以下是Doctrine手册建议对您的查询进行编码的方式:

$querybuilder = $this->_em->createQueryBuilder()
   ->select(array('c.name', 'COUNT(c.id) as co')
   ->from('My\Entity\Coupon', 'c')
   ->leftJoin('c.users', 'u')
   ->groupBy('c.id');

要在QueryBuilder中执行此连接,您需要在两个实体之间配置双向关联,您似乎尚未设置它们。

我为我的实体使用注释,但我认为YAML看起来像这样:

My\Entity\Coupon:
    manyToOne:
        users:
          targetentity: CouponUsers
           inversed-by: coupon

My\Entity\CouponUsers:
    onetoMany:
       coupon:
          targetEntity: Coupon
             mapped-by: users

如果用户可以拥有许多优惠券,那么这种关系将是双向的ManyToMany而不是manytoOne / oneToMany。有关如何配置此内容的详细信息,请参见here