这是this question的后续行动。
问题出在下面的第二行。
"".split("x"); //returns {""} // ok
"x".split("x"); //returns {} but shouldn't it return {""} because it's the string before "x" ?
"xa".split("x"); //returns {"", "a"} // see?, here "" is the first string returned
"ax".split("x"); //returns {"a"}
答案 0 :(得分:7)
不,因为根据the relevant javadoc“尾随空字符串将被丢弃”。
答案 1 :(得分:5)
根据java.util.regex.Pattern
使用的String.split(..)
source,
"".split("x"); // returns {""} - valid - when no match is found, return the original string
"x".split("x"); // returns {} - valid - trailing empty strings are removed from the resultant array {"", ""}
"xa".split("x"); // returns {"", "a"} - valid - only trailing empty strings are removed
"ax".split("x"); // returns {"a"} - valid - trailing empty strings are removed from the resultant array {"a", ""}
答案 2 :(得分:0)
要包含尾随的空字符串,请使用split
的其他实现。
"".split("x", -1); // returns {""} - valid - when no match is found, return the original string
"x".split("x", -1); // returns {"", ""} - valid - trailing empty strings are included in the resultant array {"", ""}
"xa".split("x", -1); // returns {"", "a"} - valid
"ax".split("x", -1); // returns {"a", ""} - valid - trailing empty strings are included in the resultant array {"a", ""}