Question

我正在尝试通过DAO类匹配一个hibernate实体，第一种方法有效但第二种'findByMatchingName（）'失败，下面有例外。这个条款'％？％'＆gt;有什么问题？？

public class RunnerDaoImpl extends GenericDaoImpl implements RunnerDao
{
    protected Class<Runner> getEntityClass() {
        return Runner.class;
    }

    // Works
    public List<Runner> findByExactName(String name)
    {
        return super.getHibernateTemplate().find("from Runner r where concat(r.firstname,' ',r.surname) LIKE =",new String[]{name});
    }

    // Fails
    public List<Runner> findByMatchingName(String name)
    {
        return super.getHibernateTemplate().find("from Runner r where concat(r.firstname,' ',r.surname) LIKE '%?%'",new String[]{name});
    }
}

例外

java.lang.IndexOutOfBoundsException: Remember that ordinal parameters are 1-based!
    at org.hibernate.engine.query.ParameterMetadata.getOrdinalParameterDescriptor(ParameterMetadata.java:79)
    at org.hibernate.engine.query.ParameterMetadata.getOrdinalParameterExpectedType(ParameterMetadata.java:85)
    at org.hibernate.impl.AbstractQueryImpl.determineType(AbstractQueryImpl.java:421)
    at org.hibernate.impl.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:393)
    at org.springframework.orm.hibernate3.HibernateTemplate$30.doInHibernate(HibernateTemplate.java:918)
    at org.springframework.orm.hibernate3.HibernateTemplate$30.doInHibernate(HibernateTemplate.java:1)
    at org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:406)
    at org.springframework.orm.hibernate3.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:374)
    at org.springframework.orm.hibernate3.HibernateTemplate.find(HibernateTemplate.java:912)
    at ie.bhaa.dao.RunnerDaoImpl.findByName(RunnerDaoImpl.java:15)
    at ie.bhaa.dao.RunnerDaoTest.findRunnerByName(RunnerDaoTest.java:36)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
    at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
    at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)

Answer 1

您需要将wildchar(%)添加到参数而不是查询。请修改您的第二个查询，如下所示。

// This will work!
public List<Runner> findByMatchingName(String name)
{
    return super.getHibernateTemplate().find(
    "from Runner r where concat(r.firstname,' ',r.surname) 
     LIKE ?",new String[]{"%"+name+"%"});
}

Answer 2

将%放在查询参数中而不是查询本身中，因此参数将变为"%" + name + "%"。

HQL - 请记住，序数参数是基于1的？

2 个答案: