UIScrollView中的UIPanGestureRecognizer

Question

我在UIPanGestureRecognizer：

中的UIScrollView存在以下问题

UIScrollView *sv = [[UIScrollView alloc] initWithFrame:CGRectMake(200, 200, 200, 200)];
sv.contentSize = CGSizeMake(200, 100 *100);
for (int i = 0; i < 100; i++) {
    UIView *newView = [[UIView alloc] initWithFrame:CGRectMake(0, i * 100, 200, 100)];
    UIPanGestureRecognizer *panGesture = [[UIPanGestureRecognizer alloc] initWithTarget:self action:@selector(panTile:)];
    [panGesture setDelegate:self];
    [panGesture setEnabled:FALSE];
    [newView addGestureRecognizer:panGesture];

        UILongPressGestureRecognizer *longPressRecognizer = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPress:)];
        [longPressRecognizer setDelegate:self];
        [newView addGestureRecognizer:longPressRecognizer];

        [sv addSubview:newView];
    }

完整的滚动视图中填充了小块，每个块都实现了一个平移手势，以使它们可以拖动。问题是 - 这样做 - 阻止滚动视图滚动。拖动瓷砖反而很好。当我禁用平铺手势时，滚动效果很好。瓷砖平移手势有点隐藏滚动视图自己的平移手势。我的想法是从一开始就禁用瓷砖平移手势。一旦用户长时间按下图块，就启用手势。问题是用户必须抬起手指然后再次触摸瓷砖以拖动它。拖动完成后，我启用长按并再次禁用平移手势。所以longPress:如下所示：

- (void)longPress:(UILongPressGestureRecognizer *) gestureRecognizer {
    for (UIGestureRecognizer *r in gestureRecognizer.view.gestureRecognizers) {
        if ([r isKindOfClass:[UIPanGestureRecognizer class]]) {
            [r setEnabled:TRUE];
        }
    }
    //pan gesture should take over here...
}

是否有可能将长按和平移手势粘在一起，以便用户不必抬起手指？或者可能是另一种解决方案？