Question

这是我当前的查询：

SELECT sac.cred, s.status, (SELECT NVL (csl.census_dates, tl.census_dates) 
                                         FROM  schema.sections cs,  schema.sections_ls csl,  schema.terms tl 
                                        WHERE cs.course_sections_id = csl.course_sections_id(+)AND csl.pos(+) = 1 AND cs.term = tl.terms_id 
                                          AND tl.pos = 1 AND cs.course_sections_id = cs2.course_sections_id AND ROWNUM = 1)AS censusDate, 
                                      (SELECT NVL (p.ssn, 'xxx-xx-xxxx') FROM   schema.person p 
                                        WHERE p.id = sac.person_id) AS ssn, 
                                       //schema.person_name(sac.person_id, 'FML') as fml, 
                                       //schema.person_name(sac.person_id, 'LF') as lf 
                                 FROM  schema.student_acad_cred sac JOIN  schema.statuses s 
                                   ON s.student_acad_cred_id = sac.student_acad_cred_id 
                                 JOIN  schema.terms tl ON sac.term = tl.terms_id 
                                 JOIN  schema.student_course_sec scs ON sac.student_course_sec = scs.student_course_sec_id 
                                 JOIN  schema.course_sections cs2 ON scs.course_section = cs2.course_sections_id 
                                 JOIN  schema.terms t ON tl.terms_id = t.terms_id 
                                WHERE sac.person_id = '1111111111' 
                                  AND (s.status IN ('A', 'N') OR (s.status = 'D' AND final_grade IS NOT NULL)) 
                                  AND s.pos = '1'AND tl.pos = '1' AND tl.terms_id = 'spring';

以下是结果：

cred      status   currentDate   censusDate     ssn
====      ======   ===========   ==========     ===
  3         N       11/16/2011   12/15/2011      xxx-xx-xxxx
  4         N       11/16/2011   12/15/2011      xxx-xx-xxxx
  3         N       11/16/2011   12/15/2011      xxx-xx-xxxx
  4         N       11/16/2011   12/15/2011      xxx-xx-xxxx
  1         N       11/16/2011   12/15/2011      xxx-xx-xxxx

好的，我想要做的是使用sum（）（或其他一些函数）来累计所有被拉动的学分。因此，在这种情况下，所有信用小时的总和将是“15”。有没有办法在查询中执行此操作？理想情况下我会想要这样的东西：

cred      status   currentDate   censusDate     ssn
====      ======   ===========   ==========     ===
 15         N       11/16/2011   12/15/2011      xxx-xx-xxxx

Answer 1

执行此操作的方法是GROUP BY所有其他列。由于您can't group by aliased columns directly（在Oracle和大多数RDMBSes中），您必须将整个事物包装在另一个查询中并在那里进行分组。

SELECT SUM(cred), status, censusDate, ssn 
FROM
    (SELECT sac.cred, s.status, 
          (SELECT NVL (csl.census_dates, tl.census_dates) 
             FROM  schema.sections cs,  schema.sections_ls csl,  schema.terms tl 
            WHERE cs.course_sections_id = csl.course_sections_id(+)AND csl.pos(+) = 1 AND cs.term = tl.terms_id 
              AND tl.pos = 1 AND cs.course_sections_id = cs2.course_sections_id AND ROWNUM = 1)AS censusDate, 
          (SELECT NVL (p.ssn, 'xxx-xx-xxxx') FROM   schema.person p 
            WHERE p.id = sac.person_id) AS ssn, 
           //schema.person_name(sac.person_id, 'FML') as fml, 
           //schema.person_name(sac.person_id, 'LF') as lf 
     FROM  schema.student_acad_cred sac JOIN  schema.statuses s 
       ON s.student_acad_cred_id = sac.student_acad_cred_id 
     JOIN  schema.terms tl ON sac.term = tl.terms_id 
     JOIN  schema.student_course_sec scs ON sac.student_course_sec = scs.student_course_sec_id 
     JOIN  schema.course_sections cs2 ON scs.course_section = cs2.course_sections_id 
     JOIN  schema.terms t ON tl.terms_id = t.terms_id 
    WHERE sac.person_id = '1111111111' 
      AND (s.status IN ('A', 'N') OR (s.status = 'D' AND final_grade IS NOT NULL)) 
      AND s.pos = '1'AND tl.pos = '1' AND tl.terms_id = 'spring')
GROUP BY status, censusDate, ssn;

这看起来很难看，但实际上并没有产生可怕的性能影响。

Answer 2

select groupcol, sum(cred)
from table1
group by rollup(groupcol)

在查询中添加列的行

2 个答案: