Question

我使用以下内容从地理编码中获取lat-lng ..

  $latitude = $output->results[0]->geometry->location->lat;
  $longitude = $output->results[0]->geometry->location->lng;

如何从...中提取邮政编码

{
  "status": "OK",
  "results": [ {
    "types": [ "street_address" ],
    "formatted_address": "1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA",
    "address_components": [ {
      "long_name": "1600",
      "short_name": "1600",
      "types": [ "street_number" ]
    }, {
      "long_name": "Amphitheatre Pkwy",
      "short_name": "Amphitheatre Pkwy",
      "types": [ "route" ]
    }, {
      "long_name": "Mountain View",
      "short_name": "Mountain View",
      "types": [ "locality", "political" ]
    }, {
      "long_name": "California",
      "short_name": "CA",
      "types": [ "administrative_area_level_1", "political" ]
    }, {
      "long_name": "United States",
      "short_name": "US",
      "types": [ "country", "political" ]
    }, {
      "long_name": "94043",
      "short_name": "94043",
      "types": [ "postal_code" ]
    } ],
    "geometry": {
      "location": {
        "lat": 37.4219720,
        "lng": -122.0841430
      },
      "location_type": "ROOFTOP",
      "viewport": {
        "southwest": {
          "lat": 37.4188244,
          "lng": -122.0872906
        },
        "northeast": {
          "lat": 37.4251196,
          "lng": -122.0809954
        }
      }
    }
  } ]
}

Answer 1

您可以使用以下函数来提取任何地址组件：

function extractFromAdress(components, type){
    for (var i=0; i<components.length; i++)
        for (var j=0; j<components[i].types.length; j++)
            if (components[i].types[j]==type) return components[i].long_name;
    return "";
}

要提取您致电的邮政编码：

extractFromAdress(results[0].address_components, "postal_code");

但你也可以获得其他有趣的信息：

extractFromAdress(results[0].address_components, "route");
extractFromAdress(results[0].address_components, "locality");
extractFromAdress(results[0].address_components, "country");

等...

Answer 2

我说你需要循环results.address_components。在每次迭代时检查types数组是否包含“postal_code”。如果是这样，将其保存到变量，也可能会脱离循环。虽然可能值得研究一下postal_code是否总是在address_component [5]中，这样可以省去你的循环。

如何从V3 Google maps API中提取邮政编码

2 个答案: