Question

我在PHP中执行以下操作

public $message = "<p>A new user has requested to signup for Company Name</p>
                   <p><strong>Name:</strong>". $name ."</p>
                   <p><strong>Email Address:</strong>" . $email . "</p>
                   <p><strong>Contact Number:</strong>" . $contact_number . "</p>
                   <p>Please check the attached file, for further details.</p>
                   <p>Thanks,<br/>Company Name Email Centre</p>";

正如您所看到的，我想创建一小部分HTML，其中散布着一些PHP变量，但是我收到以下错误，

解析错误：语法错误，意外'。'，期待'，'或';'

它在第31行说明这是第二个<p>标记，但是我看不到问题

Answer 1

您不应在类var定义中使用var / string连接。为什么不编写getMessage()或printMessage()或其他方法？

Answer 2

PHP在换行符处终止字符串。每次换行开始时都需要连接：

public $message = "<p>A new user has requested to signup for Company Name</p>"
                   ."<p><strong>Name:</strong>". $name ."</p>"
                   ."<p><strong>Email Address:</strong>" . $email . "</p>"
                   ."<p><strong>Contact Number:</strong>" . $contact_number . "</p>"
                   ."<p>Please check the attached file, for further details.</p>"
                   ."<p>Thanks,<br/>Company Name Email Centre</p>";

Answer 3

以这种方式试试。并查看http://php.net/manual/de/language.types.string.php

public $message = "<p>A new user has requested to signup for Company Name</p>" .
                  "<p><strong>Name:</strong>". $name ."</p>" . 
                  "<p><strong>Email Address:</strong>" . $email . "</p>" .
                  "<p><strong>Contact Number:</strong>" . $contact_number . "</p>" .
                  "<p>Please check the attached file, for further details.</p>" .
                  "<p>Thanks,<br/>Company Name Email Centre</p>";

Answer 4

public $message= "<p>A new user has requested to signup for Company Name</p>\
                   <p><strong>Name:</strong>". $name ."</p>\
                   <p><strong>Email Address:</strong>" . $email . "</p>\
                   <p><strong>Contact Number:</strong>" . $contact_number . "</p>\
                   <p>Please check the attached file, for further details.</p>\
                   <p>Thanks,<br/>Company Name Email Centre</p>";


/* Try this it will work ... ( u need to escape lines using \ ) */

Answer 5

你不能在类属性定义中这样做，而是定义属性，然后在类构造函数中给它一个值：

class Test {
    public $message;
    public $name = 'Demo Name';
    public function __construct() {
        $this->message = 'anything you want' . $this->name; # etc
    }
}

在实际定义中，您只能提供litterals，而不能进行变量评估。

干杯

在var中存储字符串会因串联而产生错误？

5 个答案: