Question

我正在寻找一种使用jQuery以多选形式获取最后一个用户选择选项的方法。

我不是要查找列表中的最后一项，而是查找用户点击的最后一项。

Answer 1

像这样的东西

var lastSelected = null;
$('.multiSelectOptions').click(function(){
    lastSelected = this.value;
});

Answer 2

当用户按住Ctrl并单击并选择多个项目时，如上面的答案中使用this.value失败 - 它会返回列表中第一个选择的值，即使这不是最后一次单击。试试这个：

var previouslySelected = [];
$("#myMultiselect").change (function() {
    // Get newly selected elements
    var currentlySelected = $(this).val();
    var newSelections = currentlySelected.filter(function (element) {
        return previouslySelected.indexOf(element) == -1;
    });
    previouslySelected = currentlySelected;

    if (newSelections.length) {
        // If there are multiple new selections, we'll take the last in the list
        var lastSelected = newSelections.reverse()[0];
    }
});

Answer 3

基本上你需要维护一个堆栈，以跟踪最后选择的项目。我写了这个函数来更新我的堆栈。

var determineLastSelectedReportNumber = function (selectedReportNumbers, oldSelectedReportNumbers) {
    var newlyAddedReportNumbers = 
    selectedReportNumbers.filter(function (n) {
        return oldSelectedReportNumbers.indexOf(n) == -1;
    });

    var removedReportNumbers = 
    oldSelectedReportNumbers.filter(function (n) {
        return selectedNumberArray.indexOf(n) == -1;
    });

    //Remove the removed reportNumbers from the stack.
    if (removedReportNumbers.length > 0) {                        
        removedReportNumbers.forEach(function (removedReportNumber) {
            for (var i = 0; i < selectedNumbersStack.length; i++) {
                if (selectedNumbersStack[i].toString() === removedReportNumber.toString()) {
                    selectedNumbersStack.splice(i, 1);
                    break;
                }
            }
        });
    }

    //Add the added reportnumbers to the stack. Push();
    if (newlyAddedReportNumbers.length > 0) {
        selectedNumbersStack.push(newlyAddedReportNumbers);
    }

    //Set the last selected from top of the stack. Peek();
    var lastSelectedReportNumber = "";
    if(selectedNumbersStack.length > 0){
        lastSelectedReportNumber = selectedNumbersStack[selectedNumbersStack.length -1];
    }

    return lastSelectedReportNumber;
}

这是我的onChange实现：

var reportNumberChanged = function () {
    var $reportNumber = $(this);
    var selectedNumber = $reportNumber.val();

    oldSelectedNumberArray = selectedNumberArray;
    selectedNumberArray = jQuery.makeArray(selectedNumber);


    var lastSelectedReportNumber = determineLastSelectedReportNumber(selectedNumberArray, oldSelectedNumberArray);
    $("#TheLastSelectedReportNumber").val(lastSelectedReportNumber);        
    resetDelayRetrieveReportInfo();
}

我不妨向您展示我的完整代码：

var selectedNumberArray = jQuery.makeArray($('#SelectedReportNumbers').val());
//Initial selectedNumbersStack.
var selectedNumbersStack = selectedNumberArray;

var counterInitialValue = 3;
var counter = counterInitialValue;
var counterInterval = -1;

function delayRetrieveReportInfo() {
    counter--;
    if (counter === 0) {
        retrieveReportInfo($("#TheLastSelectedReportNumber").val());
        clearInterval(counterInterval);
    }
}

function resetDelayRetrieveReportInfo() {
    clearInterval(counterInterval); //The previous interval is cancelled.
    counter = counterInitialValue;
    counterInterval = setInterval(function () { delayRetrieveReportInfo() }, 1000);
}

这是多选的连接：

// Hookup function to change events of select lists
$('#SelectedReportNumbers').change(reportNumberChanged);

您可以重复使用我的一些代码来创建自己的“lastSelected”实现。

如何从多选中获取最后选择的选项？

3 个答案: