Question

我有一个mysql数据库表，其结构是：

startphoneNum      |   endphoneNum      |   department
022589893232011    |   022589893232021  |   sales
022589893232027    |   022589893232029  |   Human Resources
022589893232041    |   022589893232048  |   after sales

电话号码由3部分组成：022（城市代码） - 589893232（公司号码） - 011（分机号码）

我可以使用php explode，从022-589893232-011到022589893232011格式创建一个电话号码，然后如何通过phone number放置mysql query来获取{{1} }}？

例如：

如果我拨打电话号码department name，则该号码属于022589893232043，但是如何在代码中创建after sales？得到我需要的结果？谢谢。

Answer 1

使用BETWEEN这样的查询：

SELECT department FROM table WHERE '022589893232043' BETWEEN startphoneNum AND endphoneNum;

Answer 2

尝试此查询：

SELECT department 
FROM table1 
WHERE startphoneNum >= PHP_VARIABLE AND endphoneNum <= PHP_VARIABLE

Answer 3

查看BETWEEN运算符：

$query = "SELECT department
          FROM myTable
          WHERE '$phoneNbr' BETWEEN startphoneNum AND endphoneNum;";

Answer 4

试试这个：

SELECT department FROM your_table
WHERE LEFT(your_num, 12) = LEFT(startphoneNum, 12)
  AND CONVERT(RIGHT(your_num, 3), UNSIGNED) BETWEEN
      CONVERT(RIGHT(startphoneNum, 3), UNSIGNED) AND
      CONVERT(RIGHT(endphoneNum, 3), UNSIGNED)

Answer 5

select department from [table] where [phone number] > startphonenum AND [phonenumber] < endphonenum

用实际值替换[] ...

Answer 6

从部门dp，phonenumber_table pn中选择dp.department_name，其中pn.startphonenum＆gt; 'values'和pn.endphonenum＆lt; “值

如何使mysql查询像这样的情况？

6 个答案: