Question

我有8个缩略图，当用户将鼠标悬停在其中任何一个上时，名为“target”的单独div会显示图像。默认情况下，'target'是一个空div，直到其中一个缩略图悬停。

问题： 如何设置'目标'以获得默认图像，而不会弄乱悬停的当前功能？我希望该默认图像为“图表”

<style>
#target { width: 1220px; height: 400px; }

.chart { background: url("theme/images/timeline.png") no-repeat 0 0; }

.html { background: url("theme/images/html_graph.png")  no-repeat 0 0; }
.oracle { background: url("theme/images/oracle_graph.png") no-repeat 0 0; }
.linux { background: url("theme/images/linux_graph.png") no-repeat 0 0; }
.php { background: url("theme/images/php_graph.png") no-repeat 0 0; }
.java { background: url("theme/images/java_graph.png") no-repeat 0 0; }
.prod { background: url("theme/images/prod_graph.png") no-repeat 0 0; }
.design { background: url("theme/images/design_graph.png") no-repeat 0 0; }
.pm { background: url("theme/images/pm_graph.png") no-repeat 0 0; }
</style>

<script type="text/javascript" language="Javascript/1.2">
function change(v) {
    var target = document.getElementById("target");
    if (v == "imgA") {
        target.className = "html";
    } else if (v == "imgB") {
        target.className = "oracle";
    } else if (v == "imgC") {
        target.className = "linux";
    } else if (v == "imgD") {
        target.className = "php";
    } else if (v == "imgE") {
        target.className = "java";
    } else if (v == "imgF") {
        target.className = "prod";
    } else if (v == "imgG") {
        target.className = "pm";
    } else if (v == "imgH") {
        target.className = "design";
    } else {
        target.className = "chart";
    }
}
function changeReset() {
    var target = document.getElementById("target");
    target.className = "";
}
</script>

</head>

<body>
    <div>
        <a id="imgA" onmouseover="change('imgA');" onmouseout="changeReset();" href="#"><img src="theme/images/Albania.png" alt="" /></a>
        <a id="imgB" onmouseover="change('imgB');" onmouseout="changeReset();" href="#"><img src="theme/images/Algeria.png" alt="" /></a>
        <a id="imgC" onmouseover="change('imgC');" onmouseout="changeReset();" href="#"><img src="theme/images/Brazil.png" alt="" /></a>
        <a id="imgD" onmouseover="change('imgD');" onmouseout="changeReset();" href="#"><img src="theme/images/Brunei.png" alt="" /></a>
        <a id="imgE" onmouseover="change('imgE');" onmouseout="changeReset();" href="#"><img src="theme/images/Chad.png" alt="" /></a>
        <a id="imgF" onmouseover="change('imgF');" onmouseout="changeReset();" href="#"><img src="theme/images/Chad.png" alt="" /></a>
        <a id="imgG" onmouseover="change('imgG');" onmouseout="changeReset();" href="#"><img src="theme/images/Chad.png" alt="" /></a>
        <a id="imgH" onmouseover="change('imgH');" onmouseout="changeReset();" href="#"><img src="theme/images/Chad.png" alt="" /></a>
    </div>
    <div id="target"></div></body>

Answer 1

您必须处理的代码非常严重。如果这个页面需要持续维护，或者你只想在晚上睡得更好，可以考虑使用不引人注目的javascript和一个不错的DOM操作库（如JQuery）来清理它like so。如果我理解你的问题，我相信你需要做的就是改变：

<div id="target"></div>

默认使用图表类：

<div id="target" class="chart"></div>

SIMPLE切换图像查询

1 个答案: