Question

应该很容易。我最初会在javascript中执行此操作，但必须在设置到我的处理程序页面中的表单之前执行此操作。无论如何，我需要使这些值有2位小数。例如，219333.5888888需要219333.58。是否有修剪功能？

 form.setUnitRepairCost(Double.toString(jobPlanBean.getUnitTotalCost()));   //UNIT REPAIR COST
 form.setUnitMaterialCost(Double.toString(jobPlanBean.getUnitTotalMaterialCost())); //UNIT MATERIAL COST

Answer 1

这是格式化十进制值的简单示例

import java.text.*;

public class DecimalPlaces {

    public static void main(String[] args) {

        double d = 1.234567;
        DecimalFormat df = new DecimalFormat("#.##");
        System.out.print(df.format(d));
    }

}

Answer 2

public static void main(String[] args) {

        double d = 6.3546;
        DecimalFormat df = new DecimalFormat("#.##");
        System.out.print(df.format(d));
}

Answer 3

获得双后卫而不是字符串：

double d = 80.123;
DecimalFormat df = new DecimalFormat("#.##");
double p = Double.parseDouble(df.format(d));

Answer 4

将double乘以100.0并将其转换为int然后取出该int并将其转换为double并除以100.0

    int temp = (int)(longDouble*100.0);
    double shortDouble = ((double)temp)/100.0;

Answer 5

怎么样：

new java.text.DecimalFormat("0.00").format( yourNumber );

Answer 6

这是String操作，用于将double值截断到小数位数。

public static String truncateUptoTwoDecimal(double doubleValue) {
    String value = String.valueOf(doubleValue);
    if (value != null) {
        String result = value;
        int decimalIndex = result.indexOf(".");
        if (decimalIndex != -1) {
            String decimalString = result.substring(decimalIndex + 1);
            if (decimalString.length() > 2) {
                result = value.substring(0, decimalIndex + 3);
            } else if (decimalString.length() == 1) {
                result = String.format(Locale.ENGLISH, "%.2f",
                        Double.parseDouble(value));
            }
        }
        return result;
    }
    return null;
}

Answer 7

根据其他建议，您可以使用DecimalFormat的类java.text.DecimalFormat。我们还可以使用DecimalFormat舍入十进制值。

示例：

import java.math.RoundingMode;
import java.text.DecimalFormat;

public class DecimalDemo {

    private static DecimalFormat decimalFormatter = new DecimalFormat("#.##");

    public static void main(String[] args) {

        double number = 2.14159265359;
        System.out.println("Original Number : " + number);
        System.out.println("Upto 2 decimal : " + decimalFormatter.format(number));  //2.14

        // DecimalFormat, default is RoundingMode.HALF_EVEN
        decimalFormatter.setRoundingMode(RoundingMode.DOWN);
        System.out.println("Down : " + decimalFormatter.format(number));  //2.14

        decimalFormatter.setRoundingMode(RoundingMode.UP);
        System.out.println("Up : " + decimalFormatter.format(number));    //2.15

    }

}

Answer 8

是，DecimalFormat：http://www.exampledepot.com/egs/java.text/FormatNum.html

Answer 9

使用十进制格式：

DecimalFormat twoDForm = new DecimalFormat("#.##");

Answer 10

DecimalFormat班级

Answer 11

public static double truncateDecimals(double d, int len) {
    long p = pow(10, len);
    long l = (long)(d * p);
    return (double)l / (double)p;
}

public static long pow(long a, int b) {
    long result = 1;
    for (int i = 1; i <= b; i++) {
       result *= a;
    }
    return result;
}

Answer 12

通过使用这两种方法，您还可以处理所有异常：

private String convertedBalance(String balance){
    String convertedBalance = balance.toString();
    Double d;
    try {`enter code here`
        d = Double.parseDouble(balance.toString());
        Log.i("ConvertedNumber", "d (amount) = "+d.toString());
        d = round(d, 2);

        DecimalFormat f = new DecimalFormat("0.00");
        convertedBalance = f.format(d);

        Log.i("ConvertedNumber", "convertedBalance = "+convertedBalance);

    }catch (NumberFormatException e){
        Log.i("ConvertedNumber", "Number format exception");
    }

    return convertedBalance;
}


public static double round(double value, int places) {
    if (places < 0) throw new IllegalArgumentException();

    BigDecimal bd = new BigDecimal(value);
    bd = bd.setScale(places, RoundingMode.HALF_UP);
    return bd.doubleValue();
}

修剪双精度到2位小数

12 个答案: