char buffer[128]
ret = scanf("%s %s", buffer);
这只允许我打印送入控制台的第一个字符串。如何扫描两个字符串?
答案 0 :(得分:5)
char buffer[128], buffer2[128];
ret = scanf("%s %s", buffer, buffer2);
答案 1 :(得分:3)
如果您想重复使用buffer
,则需要两次调用scanf
,每个字符串一次。
ret = scanf("%s", buffer);
/* Check that ret == 1 (one item read) and use contents of buffer */
ret = scanf("%s", buffer);
/* Check that ret == 1 (one item read) and use contents of buffer */
如果你想使用两个缓冲区,那么你可以将它组合成一个scanf
的调用:
ret = scanf("%s%s", buffer1, buffer2);
/* Check that ret == 2 (two items read) and use contents of the buffers */
请注意,读取这样的字符串本质上是不安全的,因为没有什么可以阻止来自控制台的长字符串输入溢出缓冲区。请参阅http://en.wikipedia.org/wiki/Scanf#Security。
要解决此问题,您应指定要读入的字符串的最大长度(减去终止空字符)。使用128个字符的缓冲区示例:
ret = scanf("%127s%127s", buffer1, buffer2);
/* Check that ret == 2 (two items read) and use contents of the buffers */
答案 2 :(得分:1)
您需要为第一个和第二个字符串选择两个不同的位置。
char buffer1[100], buffer2[100];
if (scanf("%99s%99s", buffer1, buffer2) != 2) /* deal with error */;
答案 3 :(得分:0)
如果您知道要阅读的单词数,可以将其读作:
char buffer1[128], buffer2[128];
ret = scanf("%s %s", buffer1, buffer2);
或者,您可以使用fgets()
函数来获取多字符串。
fgets(buffer, 128 , stdin);
答案 4 :(得分:0)
#include<stdio.h>
int main(){
int i = 0,j =0;
char last_name[10]={0};
printf("Enter sentence:");
i=scanf("%*s %s", last_name);
j=printf("String: %s",last_name)-8;
/* Printf returns number of characters printed.(String: )is adiitionally
printed having total 8 characters.So 8 is subtracted here.*/
printf("\nString Accepted: %d\nNumber of character in string: %d",i,j);
return 0;
}