Question

我编写了一个SQL查询，它将结果格式化为

ResourceName    ProjectName  TaskName Timesheet Period  ActualWork  TimeByDay  DayName

    Jim Carry        Project A   Task A   2011-12           40        09/10/2011  Monday

     Jim Carry        Project A   Task A   2011-12           70        09/10/2011  Monday
     Jim Carry        Project B   Task A   2011-12           80        09/12/2011  Tue.
     Perth S.         Project A   Task A   2011-12           35        09/10/2011  Mon.

我想编写查询，以便它给我一些类似的东西;

ResourceName    ProjectName         TaskName         Timesheet Period  Monday Tue  
Jim Carry           Project A        Task A            2011-12          110    80

正如您所看到的那样，新列在第二个查询名称中创建为星期一，星期二等等。加上总数也是根据日计算的，因此星期一列的结果是40 + 70，而星期二的结果是80 + 0。

以下是带来代码段1的查询

DECLARE @startdate DATETIME
DECLARE @enddate DATETIME

SET @startdate='1/1/2011'
SET @enddate='12/31/2011'

SELECT TOP 100 [IR.TimesheetProjectHoursByDay].ResourceName,
               [IR.TimesheetProjectHoursByDay].ProjectName,
               [IR.TimesheetProjectHoursByDay].TaskName,
               [IR.TimesheetProjectHoursByDay].PeriodName + ' ' + '(' + CONVERT(NVARCHAR, [IR.TimesheetProjectHoursByDay].PeriodStartDate, 101) + ' - ' + CONVERT(NVARCHAR, [IR.TimesheetProjectHoursByDay].PeriodEndDate, 101) + ')' AS [Timesheet Period],
               [IR.TimesheetProjectHoursByDay].ActualWork,
               [IR.TimesheetProjectHoursByDay].TimeByDay,
              DATENAME(dw,TimeByDay) as [DayName]
FROM   [IR.TimesheetProjectHoursByDay]
WHERE  [IR.TimesheetProjectHoursByDay].TimeByDay >= @StartDate
       AND [IR.TimesheetProjectHoursByDay].TimeByDay <= @EndDate
       AND [IR.TimesheetProjectHoursByDay].[Project Departments] LIKE N'CSENG'
       AND [IR.TimesheetProjectHoursByDay].ActualWork > 0
       AND [IR.TimesheetProjectHoursByDay].ResourceName LIKE '%Jim%'
GROUP  BY [IR.TimesheetProjectHoursByDay].TimeByDay,
          [IR.TimesheetProjectHoursByDay].ResourceName,
          [IR.TimesheetProjectHoursByDay].ProjectName,
          [IR.TimesheetProjectHoursByDay].TaskName,
          [IR.TimesheetProjectHoursByDay].[Project Departments],
          [IR.TimesheetProjectHoursByDay].ResourceStandardRate,
          [IR.TimesheetProjectHoursByDay].PeriodName,
          [IR.TimesheetProjectHoursByDay].PeriodStartDate,
          [IR.TimesheetProjectHoursByDay].PeriodEndDate,
          [IR.TimesheetProjectHoursByDay].ActualWork
ORDER  BY [IR.TimesheetProjectHoursByDay].TimeByDay DESC

您能否建议我在SQL查询中需要做哪些更改，以便我可以获得代码片段2中提到的结果？

让我知道所需的任何输入。请查看测试数据表，使here的内容更加清晰请指导！

谢谢！

Answer 1

鉴于你的建议并不重要，因为你只是在一天的资源工作总时数之后，你可以尝试类似的东西（注意：这是未经测试的，但是只是一个例子）;

SELECT TOP 100 [IR.TimesheetProjectHoursByDay].ResourceName,
[IR.TimesheetProjectHoursByDay].TimeByDay,
SUM([IR.TimesheetProjectHoursByDay].ActualWork) OVER(PARTITION BY [IR.TimesheetProjectHoursByDay].TimeByDay) AS "Total Hours"

然后将其用作派生表，按天组织。最近简单的谈话网站上有一个很棒的post on Window functions。请仔细阅读。这很有启发性。

Answer 2

听起来你可以使用PIVOT;看看this example。

Answer 3

如果我理解你是对的，你可以试试这个：

create table #tbl (ResourceName varchar(100), ProjectName varchar(100), TaskName varchar(100), ActualWork int, TimeByDay date)

insert into #tbl values    ('Jim Carry','Project A','Task A',40,'20111009'),
('Jim Carry','Project A','Task A',70,'20111009'),
('Jim Carry','Project B','Task B',80,'20111209'),
('Perth S.','Project A','Task A',35,'20111209')

select ResourceName,ProjectName, year(TimeByDay), MONTH(TimeByDay),
       sum(case when datename(weekday, TimeByDay)='Monday' then ActualWork else 0 end) Monday,
       sum(case when datename(weekday, TimeByDay)='Tuesday' then ActualWork else 0 end) Tuesday,
       sum(case when datename(weekday, TimeByDay)='Wednesday' then ActualWork else 0 end) Wednesday,
       sum(case when datename(weekday, TimeByDay)='Thursday' then ActualWork else 0 end) Thursday,
       sum(case when datename(weekday, TimeByDay)='Thursday' then ActualWork else 0 end) Thursday,
       sum(case when datename(weekday, TimeByDay)='Friday' then ActualWork else 0 end) Friday,
       sum(case when datename(weekday, TimeByDay)='Saturday' then ActualWork else 0 end) Saturday,
       sum(case when datename(weekday, TimeByDay)='Sunday' then ActualWork else 0 end) Sunday
from #tbl
group by ResourceName,ProjectName, year(TimeByDay), MONTH(TimeByDay)

drop table #tbl

您也可以使用PIVOT作为CJM建议。

如何重新格式化我的SQL Server查询？

3 个答案: