使用SQL和php创建每周和每月图表以用于站点使用

时间:2011-11-14 22:33:08

标签: php mysql graph generated

所以我正在建立一个我正在为工作而建立的网站的统计部分(经理要求)。我有一个'24小时'图表的功能代码。图形代码我有完美的工作,但我有麻烦得到正确的代码为mysql根据天而不是小时拉出数据

以下每小时代码

function get_hourly_graph() {
    // First lets create a daily graph for experiment then we can build on that
    date_default_timezone_set('Australia/Sydney');
    $current_hour = date('H');

    // SQL Query to get data we want
    $sql = mysql_query("SELECT hour( time_hit ) AS hour , count( hour( time_hit ) ) AS hits FROM hits WHERE time_hit > now( ) - INTERVAL 1 DAY GROUP BY hour( time_hit );")
        or die(mysql_error());

    // Remove an hour off current time for array and the loop that will put the data into the array
    $array_hour = $current_hour - 1;

    // Add a 0 if the timer is under 10. just so this is compatable with the SQL data
    if ($array_hour < 10) {
        $array_hour = 0 . $array_hour;
    }

    // initialise the array so we can set up the indexes and data in the next couple of loops
    $hit_data = array();

    // Work back the clock 24 hours and create the array indexes
    for ($i = 0; $i < 24; $i++) {
        $new_hour = $current_hour;

        if ($new_hour < 1) {
            $new_hour = 24;
            $hit_data[$new_hour] = "0";
        }
        else {
            $hit_data[$new_hour] = "0";
        }

        $current_hour = $new_hour - 1;
    }

    // Loop through  the rest of the array and replace null with 0s
    while ($results = mysql_fetch_array($sql, MYSQL_ASSOC)) {
        foreach ($hit_data as $hour => $hits) {
            if ($results['hour'] == $hour) {
                $hit_data[$hour] = $results['hits'];
            }
        }
    }

    $hit_data = array_reverse($hit_data, true);

    // Generate the graph for the 24 hour data
    generate_graph ($hit_data, '24 Hour Report', 'hourly_graph.png', 'Time (Hours)', 'Hits');
}

'hits'表基本上是3个字段'hit_id''ip_address''timestamp',它位于'YYYY-MM-DD hh:mm:ss'=“2011-08-04 12:40:34”< / p>

如何更改下面的sql代码以使用几天而不是几小时?

2 个答案:

答案 0 :(得分:1)

SELECT DATE_FORMAT('date_column', '%Y-%m-%e') as day ...... group by day

http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format

答案 1 :(得分:0)

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