Question

考虑以下事项：

import numpy as np
cimport numpy as np

DTYPE = np.float
ctypedef np.float_t DTYPE_t

def do(np.ndarray[DTYPE_t, ndim=2] hlc, int days=2):
    cdef float dvu = 0.0
    cdef Py_ssize_t N = np.shape(hlc)[1]-1, i, j, k

    cdef np.ndarray[DTYPE_t] h = hlc[0]
    cdef np.ndarray[DTYPE_t] l = hlc[1]

    cdef np.ndarray[DTYPE_t] output = np.empty(N+1, dtype=np.float)    

    for i from 0 <= i <= days-1:
        output[i] = np.NaN

    for j from N >= j >= days-1:
        for k from j >= k >= j-days+1:
            dvu += ((h[k] + l[k]) / 2.0) - 1.0
        print dvu # prints a float
        output[j] = dvu / days
        dvu = 0.0

    return output

当我发出dvu语句时，我得到一个未接地的浮点数。当我将值设置为output [j]并返回输出时，所有值都被舍入。我需要返回带有完整浮点数的输出 - 舍入。对我做错了什么的想法？

Answer 1

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Cython / Numpy：Float被截断

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