在app中我有一个Listactivity,它有一个带TextView和Button的适配器(标记为delete)。现在我想删除相应的Button点击项目。 请检查代码并建议???? `
public class MySimpleArrayAdapter extends ArrayAdapter<String> implements OnClickListener {
private final Activity context;
private final String[] names;
private Button deleteButton= null;
public MySimpleArrayAdapter(Activity context, String[] names) {
super (context, R.layout.imagelistlayout, names);
this.context = context;
this.names = names;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = context.getLayoutInflater();
View rowView = inflater.inflate(R.layout.imagelistlayout, null, true);
deleteButton= (Button)rowView.findViewById(R.id.delete_bn);
deleteButton.setTag(position);
TextView textView = (TextView) rowView.findViewById(R.id.label);
textView.setText(names[position]);
deleteButton.setOnClickListener(this);
return rowView;
}
@Override
public void onClick(View convertView) {
System.out.println(deleteButton.getTag());
}
}`
我想知道如何删除已点击按钮的项目。
答案 0 :(得分:9)
您应该尝试不在getView方法中对onClick处理程序进行硬编码,而是查看如何将onClick方法分配给listview。在这里,您可以从活动中分配方法,这也是您应该在此处执行的操作。
在你的适配器中创建一个名为setOnXXXClickListener
的方法public void setOnXXXClickListener(final OnClickListener onClickListener) {
this.onXXXClickListener = onClickListener;
}
并在你的getView中将此分配给按钮,如此
viewHolder.xxx.setOnClickListener(this.onXXXClickListener);
从你的Activity中你可以像这样分配onClick方法
this.adapter.setOnXXXClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
Log.d(TAG, "OnXXXClickListener");
}
});
答案 1 :(得分:8)
只需处理getview中的点击监听器,您可以使用findviewbyid找到该按钮
这将处理当前行按钮单击
public class MySimpleArrayAdapter extends ArrayAdapter<String> implements OnClickListener {
private final Activity context;
private final String[] names;
private Button deleteButton= null;
public MySimpleArrayAdapter(Activity context, String[] names) {
super (context, R.layout.imagelistlayout, names);
this.context = context;
this.names = names;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = context.getLayoutInflater();
View rowView = inflater.inflate(R.layout.imagelistlayout, null, true);
deleteButton= (Button)rowView.findViewById(R.id.delete_bn);
deleteButton.setTag(position);
TextView textView = (TextView) rowView.findViewById(R.id.label);
textView.setText(names[position]);
deleteButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
//try to hide textview or something it may help
}
});
return rowView;
}
}`
答案 2 :(得分:0)
deleteButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
Log.d("TAG", "position: " + position);
}
});
你需要在getView(final int position,...,...)中进行最终定位 当你拥有这个职位时,随心所欲!删除,修改或其他..
答案 3 :(得分:0)
很简单,你在getView中有位置int变量,它指的是按钮膨胀的项目,所以使用位置变量来删除你点击的项目。只需使用以下代码。
@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = context.getLayoutInflater();
View rowView = inflater.inflate(R.layout.imagelistlayout, null, true);
deleteButton= (Button)rowView.findViewById(R.id.delete_bn);
deleteButton.setTag(position);
TextView textView = (TextView) rowView.findViewById(R.id.label);
textView.setText(names[position]);
// deleteButton.setOnClickListener(this);
deleteButton.setOnClickListener(new OnClickListener()
{
@Override
public void onClick(View arg0) {
// TODO Auto-generated method stub
//use position here
// delete the item from data string havng position index and the use notifydataset
}
});
return rowView;
}