我有一个脚本,见下文:
索引页面:jQuery脚本
<script type="text/javascript">
$(document).ready(function(){
$("#loadmorebutton").click(function (){
$('#loadmorebutton').html('<img src="ajax-loader.gif" />');
$.ajax({
url: "loadmore.php?lastid=" + $(".postitem:last").attr("id"),
success: function(html){
if(html){
$("#postswrapper").append(html);
$('#loadmorebutton').html('Load More');
}else{
$('#loadmorebutton').replaceWith('<center>No more posts to show.</center>');
}
}
});
});
});
</script>
HTML:
<div id="wrapper">
<div id="postswrapper">
<?php
$getlist = mysql_query("SELECT * FROM table_name LIMIT 25");
while ($gl = mysql_fetch_array($getlist)) { ?>
<div class=postitem id="<? echo $gl['id']; ?>"><?php echo $gl['title']; ?></div>
<?php } ?>
</div>
<button id="loadmorebutton">Load More</button>
</div>
</div>
loadmore.php页面有;
<?php
$getlist = mysql_query("SELECT * FROM table_name WHERE id < '".addslashes($_GET['lastid'])."'
LIMIT 0, 25 LIMIT 10");
while ($gl = mysql_fetch_array($getlist)) { ?>
<div><?php echo $gl['title']; ?></div>
<?php } ?>
基本上这个脚本的作用是,索引页面将从数据库加载前25个项目,当你点击加载更多时,它会触发 loadmore.php ,这将加载10个以上从最后加载的id开始的数据。我想要做的是从屏幕上删除“加载更多”按钮如果数据库中少于25个项目并显示数据库中是否有超过25个项目。
答案 0 :(得分:3)
这对你有用:
<?php
$getlist = mysql_query("SELECT * FROM table_name LIMIT 25");
while ($gl = mysql_fetch_array($getlist)) { ?>
<div class=postitem id="<? echo $gl['id']; ?>"><?php echo $gl['title']; ?></div>
<?php }
if(mysql_num_rows($getlist) <= 25) { ?>
<script type="text/javascript">
$(function(){
$('#loadmorebutton').hide();
});
</script>
<?php } ?>
答案 1 :(得分:1)
<div id="wrapper">
<div id="postswrapper">
<?php
$getlist = mysql_query("SELECT * FROM table_name LIMIT 25");
**$cnt = 0;**
while ($gl = mysql_fetch_array($getlist)) { ?>
<div class=postitem id="<? echo $gl['id']; ?>"><?php echo $gl['title']; ?></div>
**$cnt++;**
<?php } ?>
</div>
**<?php if ($cnt == 24) { ?>
<button id="loadmorebutton">Load More</button>
<?php } ?>**
</div>
</div>
答案 2 :(得分:1)
将您的php脚本更改为count变量
<div id="wrapper">
<div id="postswrapper">
<?php
$count=0;
$getlist = mysql_query("SELECT * FROM table_name LIMIT 25");
while ($gl = mysql_fetch_array($getlist)) {
$count++;?>
<div class=postitem id="<? echo $gl['id']; ?>"><?php echo $gl['title']; ?></div>
<?php } ?>
</div>
<button id="loadmorebutton" value="<? echo $count ?>">Load More</button>
</div>
</div>
<script type="text/javascript">
$(document).ready(function(){
$("#loadmorebutton").click(function (){
$('#loadmorebutton').html('<img src="ajax-loader.gif" />');
$.ajax({
url: "loadmore.php?lastid=" + $(".postitem:last").attr("id"),
success: function(html){
if(html){
$("#postswrapper").append(html);
var count = patserInt($('#loadmorebutton').val());
if(count<25){
$('#loadmorebutton').html('Load More');
}else {
$('#loadmorebutton').hide();
}else{
$('#loadmorebutton').replaceWith('<center>No more posts to show.</center>');
}
}
});
});
});
</script>
答案 3 :(得分:0)
我会给你两个选项,以你们更具可读性为准。
<?php if(25 or more){ ?>
<button id="loadmorebutton">Load More</button>
<?php } ?>
<?php if(25 or more): ?>
<button id="loadmorebutton">Load More</button>
<?php endif; ?>