Question

在Java servlet中，我如何将对象置于servlet响应中？在下面的代码中，名称显示在页面上。

servlet:
private void process(HttpServletRequest request, HttpServletResponse response) throws Exception{
        String name = "John";
        System.out.println("main servlet");
        request.setAttribute("name", name);
        response.sendRedirect("index.jsp");     
    }

index.jsp in JSTL
<body>
name: ${requestScope.name}
</body>

Answer 1

将response.sendRedirect(...)替换为：

RequestDispatcher rd = request.getRequestDispatcher("index.jsp");
rd.forward(request, response);

如何将对象放到Java servlet响应中？

1 个答案: