Question

我已经有一段时间了，现在试图解决这个问题，但没有运气。

简而言之，我想采用这样的字符串："2011-11-21 11:20:00"并计算"Time Until". 在"1 day 36 mins"这样的格式中，我可以在标签中显示一个字符串。

我无法绕过这个。以前任何人都有一些示例代码吗？任何帮助将不胜感激。

Answer 1

@Maudicus走在正确的轨道上，但他的答案有一些缺陷。

您需要使用的日期格式为@"yyyy-MM-dd HH:mm:ss"

获得日期后，您应该使用-[NSCalendar components:fromDate:toDate:options:]来确定一个日期与另一个日期之间的差异。例如：

NSDate *date = ...; // the date converted using the date formatter
NSDate *target = [NSDate date]; // now
NSCalendar *calendar = [NSCalendar currentCalendar];
NSUInteger components = NSDayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit;
NSDateComponents *difference = [calendar components:components fromDate:date toDate:target options:0];

NSLog(@"difference: %d days, %d hours, %d minutes, %d seconds", [difference days], [difference hours], [difference minutes], [difference seconds]);

Answer 2

此代码可以帮助您。

    NSDate * date;

    //Assume dateString is populated and of format NSString * dateString =@"2011-11-21 11:20:00";
    NSDateFormatter * dateFormatter = [[NSDateFormatter alloc] init];

    //EDITED date formatter to correct behavior
    [dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss"];
    if (dateString != nil)  {
        date = [dateFormatter dateFromString:dateString];
    }
    [dateFormatter release];

    NSTimeInterval difference = [date timeIntervalSinceDate:[NSDate date]];
    int days = difference/(3600*24);
    difference -= (float) (days*3600*24);
    int hours = difference/(3600);
    difference -= (float) (hours*3600);
    int minutes = difference/(60);

    NSString * timeRemaining = [NSString stringWithFormat:@"%dd %dh %dm", days, hours, minutes];

Answer 3

duration.text = [NSString stringWithFormat:@"%d:%02d", (int)audioPlayer.duration / 3600, (int)audioPlayer.duration % 60, nil];

将NSString转换为时间，然后计算“Time Until”

3 个答案: