Question

如何在PHP中将"2011-11-03T17:27:56Z"转换为时间。

我希望与当前时间有所不同。

即。如果与当前时间的时差是10分钟，我想要10分钟。如果它是1天，那么我想要1天。

Answer 1

这个小片段将为您提供从现在到给定日期之间的秒数差异。

$dateString = "2011-11-03T17:27:56Z";
$date = strtotime($dateString);
$diff = time() - $date;
echo $diff;

要为其提供您要求的特定格式，可以使用我发现的here以下功能：

function time_diff($s) { 
    $m = 0; $hr = 0; $d = 0; $td = "now";
    if ($s > 59) { 
        $m = (int)($s/60); 
        $s = $s-($m*60); // sec left over 
        $td = "$m min"; 
    } 
    if ($m > 59) { 
        $hr = (int)($m / 60); 
        $m = $m - ($hr*60); // min left over 
        $td = "$hr hr"; 
        if ($hr > 1) {
            $td .= "s";
        }
        if ($m > 0) {
            $td .= ", $m min";
        }
    } 
    if ($hr > 23) { 
        $d = (int) ($hr / 24); 
        $hr = $hr-($d*24); // hr left over 
        $td = "$d day"; 
        if ($d > 1) {
            $td .= "s";
        }
        if ($d < 3) { 
            if ($hr > 0) {
                $td .= ", $hr hr";
            }
            if ($hr > 1) {
                $td .= "s";
            }
        } 
    } 
    return $td; 
}

结合这两者就是你得到的：

$dateString = "2011-11-03T17:27:56Z";
$date = strtotime($dateString);
$diff = time() - $date;
echo time_diff($diff);

输出：

8天

Answer 2

$diffInSecs = time() - strtotime('2011-11-03T17:27:56Z');

Answer 3

工作示例：（codepad here）

<?php

$time_str = "2011-11-03T17:27:56Z";

//echo date('d/m/y H:i:s', strtotime($time_str));
$diff = abs(strtotime("now") - strtotime($time_str)); 

$years   = floor($diff / (365*60*60*24)); 
$months  = floor(($diff - $years * 365*60*60*24) / (30*60*60*24)); 
$days    = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$hours   = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60)); 
$minuts  = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60); 
$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60)); 
printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);

（时间差异在这里：How to calculate the difference between two dates using PHP?）

Answer 4

我相信你想要strtotime()功能：

$some_time = strtotime("2011-11-03T17:27:56Z");//outputs a UNIX TIMESTAMP
$time_diff = (time() - $some_time);
if ($time_diff > 86400) {
    echo round($time_diff / 86400) . " days";
} else if ($time_diff > 3600) {
    echo round($time_diff / 3600) . " hours";
} else {
    echo round($time_diff / 60) . " minutes";
}

http://us.php.net/manual/en/function.strtotime.php

该函数需要一个包含英文日期的字符串格式并将尝试将该格式解析为Unix时间戳

在php中将字符串转换为时间

4 个答案: