Question

我有一个index.php文件，通过这个javascript / ajax代码加载其他php文件：

function AJAX(elementID,url,showStatus){
var httpObject;
if (window.ActiveXObject) {
    httpObject = new ActiveXObject("Microsoft.XMLHTTP");
}
if (window.XMLHttpRequest){
    httpObject =  new XMLHttpRequest();
}
else {
    alert("Your browser does not support AJAX.");       
}

if (httpObject != null) {
    httpObject.onreadystatechange = function() {          
        if (elementID != false){                

            if (httpObject.readyState == 4 && httpObject.status == 200) {                  
                document.getElementById(elementID).innerHTML= httpObject.responseText;  

            } 
        }

    }

    httpObject.open("POST",url,true);
    httpObject.send(null);  
}
}

所以例如我会在inxex.php中加载一个文件：

<script>
AJAX("updateThisDiv", "/includes/contentpage.php", false)
</script>

会粘贴＆＃34; contentpage.php＆＃34;的内容进入div＆＃34; updateThisDiv＆＃34;但是现在如果我在＆＃34; contentpage.php＆＃34;上有任何javascript，它将无法运行，有没有办法做到这一点？

我看过这个：http://www.javascriptkit.com/script/script2/ajaxpagefetcher.shtml 但它并不是我想要的。

我希望能够在不重新加载整个页面的情况下更新页面的一部分并且必须运行javascript

Answer 1

如果动态插入脚本标记，代码将执行。不要使用EVAL。图书馆知道这一点，他们也不使用eval（除非它们很糟糕）。

Answer 2

如果您想按需加载Javascript。这可以通过动态创建脚本标记来完成。这种模式在Stoyan Stefanov书中说明 - Javascript Patterns

这本书摘自：

编写一个require函数。然后这样称呼：

require("extra.js", function () {
    functionDefinedInExtraJS();
});

样品需要功能：

function require(file, callback) {

    var script = document.getElementsByTagName('script')[0],
        newjs = document.createElement('script');

    // IE
    newjs.onreadystatechange = function () {
        if (newjs.readyState === 'loaded' || newjs.readyState === 'complete') {
            callback();
        }
    };

    // others
    newjs.onload = function () {
        callback();
    };

    newjs.src = file;
    script.parentNode.insertBefore(newjs, script);
}

在http://www.jspatterns.com/book/8/ondemand.html

中找到实时示例

@Edit：针对您的案例的更多细节。我会尽量简单：

创建四个文件：

index.php：测试文件。
code.js：具有Ajax，getJS，getHTML函数的实际代码
content.php：任何将在没有任何JS的情况下打印纯HTML的PHP文件
content.js：您想要动态运行的JavaScript代码。

的index.php

<html>
    <head>
        <script src="code.js"></script>
    </head>
    <body>
        <input type="button" onclick="Ajax('content.php', 'd_html');" value="Fill from content.php"/>
        <div id="d_html"></div>
        <br>
        <input type="button" onclick="Ajax('content.js', 'd_js');" value="Fill from content.js"/>
        <div id="d_js"></div>
    </body>
</html>

content.php

<span>Hello, I am dynamic span came from content.php</span>

content.js

//Ana javascript code you want to run it by Ajax function should go inside this function
function executeJS(element){
   element.innerHTML = "<span>Hello, I am dynamic span came from content.js</span>";
}

code.js

//This function responsible for doing the ajax request for any file that will return pure HTML.
function getHTML(url, element){
    var i, xhr, activeXids = [
        'MSXML2.XMLHTTP.3.0',
        'MSXML2.XMLHTTP',
        'Microsoft.XMLHTTP'
    ];

    if (typeof XMLHttpRequest === "function") { // native XHR
        xhr =  new XMLHttpRequest();        
    } else { // IE before 7
        for (i = 0; i < activeXids.length; i += 1) {
            try {
                xhr = new ActiveXObject(activeXids[i]);
                break;
            } catch (e) {}
        }
    }

    xhr.onreadystatechange = function () {
        if (xhr.readyState !== 4) {
            return false;
        }
        if (xhr.status !== 200) {
            alert("Error, status code: " + xhr.status);
            return false;
        }

        element.innerHTML += xhr.responseText;
    };

    xhr.open("GET", url, true); 
    xhr.send("");
}

//This function will load javascript file on-demand and call executeJS function inside that file.
function getJS(url, element, cb){
    var newjs = document.createElement('script');

    // IE
    newjs.onreadystatechange = function () {
        if (newjs.readyState === 'loaded' || newjs.readyState === 'complete') {
            cb();
        }
    };

    // others
    newjs.onload = function () {
        cb();
    };

    newjs.src = url;
    element.appendChild(newjs);
}


//This is same as your function, but now can handle both PHP and JS files
function Ajax(url, id){
    var element = document.getElementById(id),
        regex = /\.js$/;
    if(!element){
        alert("Invalid ID");
        return false;
    }

    if(regex.test(url)){ //If url ends with JS, load using getJS
        getJS(url, element, function(){
            executeJS(element);
        });
    } else {
        getHTML(url, element);
    }
}

Answer 3

这100％工作.....但我宁愿不使用jquery

<!DOCTYPE html>
<html dir=”ltr” lang=”en-US”>
<head>
    <meta charset=”UTF-8” />
    <title>AJAX Detection And Data Loading Using New School jQuery & HTML5:</title>            
    <script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.js” 
type=”text/javascript”></script>
    <script type="text/javascript">
        $(document).ready(function(){
            $("button").click(function () {
                $("#mm").load("test.php");
            });
        });
    </script>
</head>
<body>
    <button type=”button”>Load Some Copy!</button>
    <div id="mm">
    </div>
    <section>
    </section>
</body>
</html>

如何在通过ajax加载的html中运行javascript

3 个答案: