我希望大家都知道我的数据库中的表是如何相互关联的（即PK / FK / UK），因此我创建了SQL Server中所有表的数据库图表。创建的图表不易读取，必须滚动（水平，有时垂直）以查看另一端的表格。
简而言之，在了解许多表之间的关系时，SQL的db图表不是UI友好的。
我的（简单）问题：是否有像数据库图这样的东西可以用“好”的方式做db图表做的事情？
答案 0 :(得分：92)
有时，文字表示也可能有所帮助;通过对系统目录视图的查询，您可以获得所有FK关系的列表以及链接两个表（以及它们操作的列）的链接。
SELECT
fk.name 'FK Name',
tp.name 'Parent table',
cp.name, cp.column_id,
tr.name 'Refrenced table',
cr.name, cr.column_id
FROM
sys.foreign_keys fk
INNER JOIN
sys.tables tp ON fk.parent_object_id = tp.object_id
INNER JOIN
sys.tables tr ON fk.referenced_object_id = tr.object_id
INNER JOIN
sys.foreign_key_columns fkc ON fkc.constraint_object_id = fk.object_id
INNER JOIN
sys.columns cp ON fkc.parent_column_id = cp.column_id AND fkc.parent_object_id = cp.object_id
INNER JOIN
sys.columns cr ON fkc.referenced_column_id = cr.column_id AND fkc.referenced_object_id = cr.object_id
ORDER BY
tp.name, cp.column_id
将其转储到Excel中，您可以根据父表，引用的表或其他任何内容进行切片和切块。
我发现视觉指南很有用 - 但有时，文字文档也同样好（甚至更好） - 只需要我的2美分......
答案 1 :(得分：7)
或者您可以查看schemacrawler
答案 2 :(得分：2)
Microsoft Visio可能是我遇到过的最好的，但据我所知，它不会根据您的关系自动生成。
编辑：在Visio中尝试此操作，可以为您提供所需内容http://office.microsoft.com/en-us/visio-help/reverse-engineering-an-existing-database-HA001182257.aspx
答案 3 :(得分：2)
使用INFORMATION_SCHEMA
检索相同数据的另一种方法SQL Server中包含的信息架构视图符合INFORMATION_SCHEMA的ISO标准定义。
SELECT
K_Table = FK.TABLE_NAME,
FK_Column = CU.COLUMN_NAME,
PK_Table = PK.TABLE_NAME,
PK_Column = PT.COLUMN_NAME,
Constraint_Name = C.CONSTRAINT_NAME
FROM INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS C
INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS FK ON C.CONSTRAINT_NAME = FK.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS PK ON C.UNIQUE_CONSTRAINT_NAME = PK.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE CU ON C.CONSTRAINT_NAME = CU.CONSTRAINT_NAME
INNER JOIN (
SELECT i1.TABLE_NAME, i2.COLUMN_NAME
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS i1
INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE i2 ON i1.CONSTRAINT_NAME = i2.CONSTRAINT_NAME
WHERE i1.CONSTRAINT_TYPE = 'PRIMARY KEY'
) PT ON PT.TABLE_NAME = PK.TABLE_NAME
---- optional:
ORDER BY
1,2,3,4
WHERE PK.TABLE_NAME='something'WHERE FK.TABLE_NAME='something'
WHERE PK.TABLE_NAME IN ('one_thing', 'another')
WHERE FK.TABLE_NAME IN ('one_thing', 'another')
答案 4 :(得分：1)
此存储过程将为您提供关系的分层树。基于Technet的article。它还可以选择为您提供读取或删除所有相关数据的查询。
IF OBJECT_ID('GetForeignKeyRelations','P') IS NOT NULL
DROP PROC GetForeignKeyRelations
GO
CREATE PROC GetForeignKeyRelations
@Schemaname Sysname = 'dbo'
,@Tablename Sysname
,@WhereClause NVARCHAR(2000) = ''
,@GenerateDeleteScripts bit = 0
,@GenerateSelectScripts bit = 0
AS
SET NOCOUNT ON
DECLARE @fkeytbl TABLE
(
ReferencingObjectid int NULL
,ReferencingSchemaname Sysname NULL
,ReferencingTablename Sysname NULL
,ReferencingColumnname Sysname NULL
,PrimarykeyObjectid int NULL
,PrimarykeySchemaname Sysname NULL
,PrimarykeyTablename Sysname NULL
,PrimarykeyColumnname Sysname NULL
,Hierarchy varchar(max) NULL
,level int NULL
,rnk varchar(max) NULL
,Processed bit default 0 NULL
);
WITH fkey (ReferencingObjectid,ReferencingSchemaname,ReferencingTablename,ReferencingColumnname
,PrimarykeyObjectid,PrimarykeySchemaname,PrimarykeyTablename,PrimarykeyColumnname,Hierarchy,level,rnk)
AS
(
SELECT
soc.object_id
,scc.name
,soc.name
,convert(sysname,null)
,convert(int,null)
,convert(sysname,null)
,convert(sysname,null)
,convert(sysname,null)
,CONVERT(VARCHAR(MAX), scc.name + '.' + soc.name ) as Hierarchy
,0 as level
,rnk=convert(varchar(max),soc.object_id)
FROM SYS.objects soc
JOIN sys.schemas scc
ON soc.schema_id = scc.schema_id
WHERE scc.name =@Schemaname
AND soc.name =@Tablename
UNION ALL
SELECT sop.object_id
,scp.name
,sop.name
,socp.name
,soc.object_id
,scc.name
,soc.name
,socc.name
,CONVERT(VARCHAR(MAX), f.Hierarchy + ' --> ' + scp.name + '.' + sop.name ) as Hierarchy
,f.level+1 as level
,rnk=f.rnk + '-' + convert(varchar(max),sop.object_id)
FROM SYS.foreign_key_columns sfc
JOIN Sys.Objects sop
ON sfc.parent_object_id = sop.object_id
JOIN SYS.columns socp
ON socp.object_id = sop.object_id
AND socp.column_id = sfc.parent_column_id
JOIN sys.schemas scp
ON sop.schema_id = scp.schema_id
JOIN SYS.objects soc
ON sfc.referenced_object_id = soc.object_id
JOIN SYS.columns socc
ON socc.object_id = soc.object_id
AND socc.column_id = sfc.referenced_column_id
JOIN sys.schemas scc
ON soc.schema_id = scc.schema_id
JOIN fkey f
ON f.ReferencingObjectid = sfc.referenced_object_id
WHERE ISNULL(f.PrimarykeyObjectid,0) <> f.ReferencingObjectid
)
INSERT INTO @fkeytbl
(ReferencingObjectid,ReferencingSchemaname,ReferencingTablename,ReferencingColumnname
,PrimarykeyObjectid,PrimarykeySchemaname,PrimarykeyTablename,PrimarykeyColumnname,Hierarchy,level,rnk)
SELECT ReferencingObjectid,ReferencingSchemaname,ReferencingTablename,ReferencingColumnname
,PrimarykeyObjectid,PrimarykeySchemaname,PrimarykeyTablename,PrimarykeyColumnname,Hierarchy,level,rnk
FROM fkey
SELECT F.Relationshiptree
FROM
(
SELECT DISTINCT Replicate('------',Level) + CASE LEVEL WHEN 0 THEN '' ELSE '>' END + ReferencingSchemaname + '.' + ReferencingTablename 'Relationshiptree'
,RNK
FROM @fkeytbl
) F
ORDER BY F.rnk ASC
-------------------------------------------------------------------------------------------------------------------------------
-- Generate the Delete / Select script
-------------------------------------------------------------------------------------------------------------------------------
DECLARE @Sql VARCHAR(MAX)
DECLARE @RnkSql VARCHAR(MAX)
DECLARE @Jointables TABLE
(
ID INT IDENTITY
,Object_id int
)
DECLARE @ProcessTablename SYSNAME
DECLARE @ProcessSchemaName SYSNAME
DECLARE @JoinConditionSQL VARCHAR(MAX)
DECLARE @Rnk VARCHAR(MAX)
DECLARE @OldTablename SYSNAME
IF @GenerateDeleteScripts = 1 or @GenerateSelectScripts = 1
BEGIN
WHILE EXISTS ( SELECT 1
FROM @fkeytbl
WHERE Processed = 0
AND level > 0 )
BEGIN
SELECT @ProcessTablename = ''
SELECT @Sql = ''
SELECT @JoinConditionSQL = ''
SELECT @OldTablename = ''
SELECT TOP 1 @ProcessTablename = ReferencingTablename
,@ProcessSchemaName = ReferencingSchemaname
,@Rnk = RNK
FROM @fkeytbl
WHERE Processed = 0
AND level > 0
ORDER BY level DESC
SELECT @RnkSql ='SELECT ' + REPLACE (@rnk,'-',' UNION ALL SELECT ')
DELETE FROM @Jointables
INSERT INTO @Jointables
EXEC(@RnkSql)
IF @GenerateDeleteScripts = 1
SELECT @Sql = 'DELETE [' + @ProcessSchemaName + '].[' + @ProcessTablename + ']' + CHAR(10) + ' FROM [' + @ProcessSchemaName + '].[' + @ProcessTablename + ']' + CHAR(10)
IF @GenerateSelectScripts = 1
SELECT @Sql = 'SELECT [' + @ProcessSchemaName + '].[' + @ProcessTablename + '].*' + CHAR(10) + ' FROM [' + @ProcessSchemaName + '].[' + @ProcessTablename + ']' + CHAR(10)
SELECT @JoinConditionSQL = @JoinConditionSQL
+ CASE
WHEN @OldTablename <> f.PrimarykeyTablename THEN 'JOIN [' + f.PrimarykeySchemaname + '].[' + f.PrimarykeyTablename + '] ' + CHAR(10) + ' ON '
ELSE ' AND '
END
+ ' [' + f.PrimarykeySchemaname + '].[' + f.PrimarykeyTablename + '].[' + f.PrimarykeyColumnname + '] = [' + f.ReferencingSchemaname + '].[' + f.ReferencingTablename + '].[' + f.ReferencingColumnname + ']' + CHAR(10)
, @OldTablename = CASE
WHEN @OldTablename <> f.PrimarykeyTablename THEN f.PrimarykeyTablename
ELSE @OldTablename
END
FROM @fkeytbl f
JOIN @Jointables j
ON f.Referencingobjectid = j.Object_id
WHERE charindex(f.rnk + '-',@Rnk + '-') <> 0
AND F.level > 0
ORDER BY J.ID DESC
SELECT @Sql = @Sql + @JoinConditionSQL
IF LTRIM(RTRIM(@WhereClause)) <> ''
SELECT @Sql = @Sql + ' WHERE (' + @WhereClause + ')'
PRINT @SQL
PRINT CHAR(10)
UPDATE @fkeytbl
SET Processed = 1
WHERE ReferencingTablename = @ProcessTablename
AND rnk = @Rnk
END
IF @GenerateDeleteScripts = 1
SELECT @Sql = 'DELETE FROM [' + @Schemaname + '].[' + @Tablename + ']'
IF @GenerateSelectScripts = 1
SELECT @Sql = 'SELECT * FROM [' + @Schemaname + '].[' + @Tablename + ']'
IF LTRIM(RTRIM(@WhereClause)) <> ''
SELECT @Sql = @Sql + ' WHERE ' + @WhereClause
PRINT @SQL
END
SET NOCOUNT OFF
go
答案 5 :(得分：0)
我的解决方案基于@marc_s解决方案，我只是在约束基于多个列的情况下连接列：
SELECT
FK.[name] AS ForeignKeyConstraintName
,SCHEMA_NAME(FT.schema_id) + '.' + FT.[name] AS ForeignTable
,STUFF(ForeignColumns.ForeignColumns, 1, 2, '') AS ForeignColumns
,SCHEMA_NAME(RT.schema_id) + '.' + RT.[name] AS ReferencedTable
,STUFF(ReferencedColumns.ReferencedColumns, 1, 2, '') AS ReferencedColumns
FROM
sys.foreign_keys FK
INNER JOIN sys.tables FT
ON FT.object_id = FK.parent_object_id
INNER JOIN sys.tables RT
ON RT.object_id = FK.referenced_object_id
CROSS APPLY
(
SELECT
', ' + iFC.[name] AS [text()]
FROM
sys.foreign_key_columns iFKC
INNER JOIN sys.columns iFC
ON iFC.object_id = iFKC.parent_object_id
AND iFC.column_id = iFKC.parent_column_id
WHERE
iFKC.constraint_object_id = FK.object_id
ORDER BY
iFC.[name]
FOR XML PATH('')
) ForeignColumns (ForeignColumns)
CROSS APPLY
(
SELECT
', ' + iRC.[name]AS [text()]
FROM
sys.foreign_key_columns iFKC
INNER JOIN sys.columns iRC
ON iRC.object_id = iFKC.referenced_object_id
AND iRC.column_id = iFKC.referenced_column_id
WHERE
iFKC.constraint_object_id = FK.object_id
ORDER BY
iRC.[name]
FOR XML PATH('')
) ReferencedColumns (ReferencedColumns)
答案 6 :(得分：0)
select * from information_schema.REFERENTIAL_CONSTRAINTS where
UNIQUE_CONSTRAINT_SCHEMA = 'TABLE_NAME'
这将列出包含TABLE_NAME和REFERENCED_COLUMN_NAME。