我有一个多语种数据库(灵感来自here, the 3rd option。)
我的数据库架构如下所示:
Article: (id, fk_name, fk_description, fk_reference, fk_um)
Translation: (id)
TranslationText: (id, fk_translation, fk_language,text)
Language (id, name)
Article --(M:1)--> Translation --(1:M)--> TranslationText --(M:1)--> Language
我正在使用带有Doctrine的Symfony 2,我需要一份针对某种语言的所有文章的报告(作为参数传递)。
当文章在特定语言中包含名称,描述或参考但问题时,问题就会出现没有嗯(至少不是所要求的语言)。
到目前为止,我最好的方法是这个SQL,由于缺少嵌套连接,我无法在Doctrine 2中实现。( language_id = 28 )
select ing.*
, tx_name.text, tx_description.text, tx_reference.text, tx_um.text
from Article ing
left join (Translation t_name left
join TranslationText tx_name
on t_name.id = tx_name.fk_translation
and tx_name.fk_language = 28)
on ing.fk_name = t_name.id
left join (Translation t_description
left join TranslationText tx_description
on t_description.id = tx_description.fk_translation
and tx_description.fk_language = 28)
on ing.fk_description = t_description.id
left join (Translation t_reference
left join TranslationText tx_reference
on t_reference.id = tx_reference.fk_translation
and tx_reference.fk_language = 28)
on ing.fk_reference = t_reference.id
left join (Translation t_um
left join TranslationText tx_um
on t_um.id = tx_um.fk_translation
and tx_um.fk_language = 28)
on ing.fk_um = t_um.id
;
是否有简化查询并使其在Doctrine的DQL中工作?
亲切的问候,
Dan Cearnau
答案 0 :(得分:1)
我会尝试编写没有子选择(子连接)的查询: 缩进连接与dbms p.o.v处于同一级别,但对我们而言依赖于以前的表。
select ing.*
, tx_name.text
, tx_description.text
, tx_reference.text
, tx_um.text
from Article ing
left join Translation t_name on ing.fk_name = t_name.id
left join TranslationText tx_name
on (t_name.id = tx_name.fk_translation
and tx_name.fk_language = 28)
left join Translation t_description on ing.fk_description = t_description.id
left join TranslationText tx_description
on (t_description.id = tx_description.fk_translation
and tx_description.fk_language = 28)
left join Translation translation_reference on ing.fk_reference = translation_reference.id
left join TranslationText tx_reference
on (translation_reference.id = tx_reference.fk_translation
and tx_reference.fk_language = 28)
left join Translation translation_um on ing.fk_um = translation_um.id
left join TranslationText tx_um
on (translation_um.id = tx_um.fk_translation
and tx_um.fk_language = 28);
另外,我认为你的模型过于标准化了。 对我来说,这更好:
Article: (id, another_columns)
TranslationText: (fk_article_id, fk_language,name_text, description_text, reference_text, um_text)
Language (id, name)
正如我现在所看到的,这是模型表明您link
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