Question

我有一个

tableD (ID int, matchID char, PID char, set int, num char, status char, msg char)

ID  matchID  PID   set  num  status  msg
1   00A123   xx123  1   11  
2   00B247   xx213  1   13
3   00H417   xx317  2   15
4   00G547   xx328  3   16
5   00Y547   xx721  3   19

TableP 

PID    num
xx213  13
...................

现在我们必须将status = void设置在同一个集合中，

对于PID和tabled中的同一tableP，tableP中不存在不同的num或记录。如果[num]中至少存在一个对应的tableP，则适用此选项。保持一个匹配并且对所有其他人进行VOID。同样在[msg]中，它应该说__是匹配的[ID]。
如果同一组中没有匹配，请传递具有最低[matchID]的那个，并使用相同的msg使所有其他组无效。另外[matchID]始终为00*xxxxxxx (10 digit) * is alphabet和x is (0-9)。

预期结果：

ID  matchID  PID   set  num  status  msg
1   00A123   xx123  1   11   VOID    <duplicate of ID = 2>
2   00B247   xx213  1   13   NULL    NULL
3   00H417   xx317  2   15   NULL    NULL
4   00G547   xx328  3   16   NULL    NULL (G<Y)
5   00Y547   xx721  3   19   VOID    <duplicate of ID = 4>

我试过了：

;WITH setInfo AS (
SELECT [SET], 
    CASE WHEN EXISTS (SELECT 1 FROM tableD b 
                                WHERE b.[set]=a.[set] AND num IS NOT NULL) 
                                THEN 1 ELSE 0 END AS HasNum,
    MIN(matchID) AS MinMatchPID
FROM tableD a
GROUP BY [SET]
)

UPDATE a SET
PID = CASE WHEN s.HasNum = 0 AND a.PID = s.MinMatchPID THEN a.ID
                         WHEN s.HasNum = 1 AND a.PID = (SELECT min(MatchID) FROM tableD b
                                                                        WHERE b.[set] = a.[set]
                                                                        AND b.num is not null) THEN a.PID
                    END

FROM TableD a
JOIN setInfo s ON s.[set] = a.[set]


;WITH CTE_Duplicates1 AS
  (SELECT MIN(ID) OVER (PARTITION BY [set]) Mn1,
  ROW_NUMBER() OVER (PARTITION BY [set]
 ORDER BY ID) RN,*
  FROM tableD )

 UPDATE CTE_Duplicates1
 SET status = 'VOID',
     Message = '<V-Duplicate of ID=' + CAST(Mn1 as VARCHAR(15))+'>'
 WHERE RN>1

没有给出准确的结果。

SQL Server：表中的两个方案

0 个答案: