我有一个MySQL查询:
SELECT concat_ws(title,description) as concatenated HAVING concatenated LIKE '%SearchTerm%';
我的表格用myISAM编码utf8_general_ci。
搜索似乎区分大小写。
我无法弄清楚如何修复它。出了什么问题和/或我该如何解决?
答案 0 :(得分:41)
在性能方面更好的解决方案:
SELECT .... FROM .... WHERE `concatenated` LIKE BINARY '%SearchTerm%';
当任何操作数是二进制字符串时,字符串比较区分大小写。
另一种方法是使用COLLATE
,
SELECT ....
FROM ....
WHERE `concatenated` like '%SearchTerm%' COLLATE utf8_bin;
答案 1 :(得分:18)
试试这个:
SELECT LOWER(CONCAT_WS(title,description)) AS concatenated
WHERE concatenated LIKE '%searchterm%'
或(让你看到差异)
SELECT LOWER(CONCAT_WS(title,description)) AS concatenated
WHERE concatenated LIKE LOWER('%SearchTerm%')
答案 2 :(得分:5)
在此方法中,您不必选择搜索的字段:
SELECT table.id
FROM table
WHERE LOWER(table.aTextField) LIKE LOWER('%SearchAnything%')
答案 3 :(得分:0)
这也有效:
SELECT LOWER(DisplayName) as DN
FROM Bidders
WHERE OrgID=45
HAVING DN like "cbbautos%"
LIMIT 10;
答案 4 :(得分:0)
检查表架构中提到的CHARSET:
show create table xyz;
基于CHARSET,您可以尝试以下方法。
select name from xyz where name like '%Man%' COLLATE latin1_bin;
select name from xyz where name like '%Man%' COLLATE utf8_bin;
以下是适用于我的案例,CHARSET = latin1,MySQL版本= 5.6。
mysql> select installsrc from appuser where installsrc IS NOT NULL and installsrc like 'Promo%' collate latin1_bin limit 1;
+-----------------------+
| installsrc |
+-----------------------+
| PromoBalance_SMS,null |
+-----------------------+
1 row in set (0.01 sec)
mysql>
mysql> select installsrc from appuser where installsrc IS NOT NULL and installsrc like 'PROMO%' collate latin1_bin limit 1;
+---------------------------+
| installsrc |
+---------------------------+
| PROMO_SMS_MISSEDCALL,null |
+---------------------------+
1 row in set (0.00 sec)
mysql> select installsrc from appuser where installsrc IS NOT NULL and installsrc like 'PROMO%' limit 1;
+-----------------------+
| installsrc |
+-----------------------+
| PromoBalance_SMS,null |
+-----------------------+
1 row in set (0.01 sec)
答案 5 :(得分:0)
只是为了完成,如果有帮助:
如https://dev.mysql.com/doc/refman/5.7/en/case-sensitivity.html所述,对于默认字符集,非二进制字符串比较默认情况下不区分大小写。
因此,执行不区分大小写的比较的简单方法是将字段转换为CHAR,VARCHAR或TEXT类型。
以下是针对单个字段进行检查的示例:
SELECT * FROM table1 WHERE CAST(`field1` AS CHAR) LIKE '%needle%';
答案 6 :(得分:-1)
这是工作代码:
SELECT title,description
FROM (
SELECT title,description, LOWER(CONCAT_WS(title,description)) AS concatenated
FROM table1
) AS Q
WHERE concatenated LIKE LOWER('%search%')
答案 7 :(得分:-1)
由于表中使用的排序规则,在这种情况下会出现此问题。您已使用utf8_general_ci
作为排序规则。如果排序规则更改为utf8_general_ci
,则搜索不会区分大小写。
因此,一种可能的解决方案是更改排序规则。