Question

希望一切顺利。我有一些问题，没有随机选择一个IP。我会尝试解释。

<select name="State">
<option value="0" selected="selected">Select a State</option>
<option value="AL">Alabama</option>
<option value="AK">Alaska</option>
<option value="AZ">Arizona</option>
<option value="AR">Arkansas</option>
   etc.....
</select>

任何时候客户选择一个状态并将表单提交到我的数据库并将一个ip地址提取到状态。这就是我的数据库的样子

+-------+---------------+
| state |      ip       |
+-------+---------------+
| AL    | 67.100.244.74 |
| AK    | 68.20.131.135 |
| AZ    | 64.134.225.33 |
+-------+---------------+

感谢此论坛上的人们，我有一些PHP代码，在提交表单时收集IP地址并将其发送到我的电子邮箱。完善。这是代码

<?php
// visit http://php.net/pdo for more details
// start error handling

try 
{
  // connect
  $pdo = new PDO('mysql:host=localhost;dbname=name', 'dbuser', 'pass');
  // enable error handling through exceptions
  $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
  // create safe query
  $query = $pdo->prepare("SELECT ip FROM vincer WHERE state = ? ORDER BY RAND() LIMIT 1");
  // pass data & execute query (since the data are of string type
  // and therefore can be passed in this lazy way)
  $query->execute(array($_POST['State']));
  // get value
  $ip = $query->fetchColumn();
  // print out the IP address using $ip
}
catch (Exception $e)
{
  echo "sorry, there was an error.";
  mail("email@gmail.com", "database error", $e->getMessage(), "From: email@gmail.com");
}
?><?php

if(isset($_POST['email'])) {

    // EDIT THE 2 LINES BELOW AS REQUIRED
    $email_to = "1stoptutorials@gmail.com";
    $email_subject = "This is a test";


    function died($error) {
        // your error code can go here
        echo "We are very sorry, but there were error(s) found with the form you submitted. ";
        echo "These errors appear below.<br /><br />";
        echo $error."<br /><br />";
        echo "Please go back and fix these errors.<br /><br />";
        die();
    }

    // validation expected data exists
    if(!isset($_POST['first_name']) ||
        !isset($_POST['last_name']) ||
        !isset($_POST['email']) ||
        !isset($_POST['State']) ||
        !isset($_POST['comments'])) {
        died('We are sorry, but there appears to be a problem with the form you submitted.');       
    }

    $first_name = $_POST['first_name']; // required
    $last_name = $_POST['last_name']; // required
    $email_from = $_POST['email']; // required
    $state = $_POST['State']; // not required
    $comments = $_POST['comments']; // required

    $error_message = "";
    $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
  if(!preg_match($email_exp,$email_from)) {
    $error_message .= 'The Email Address you entered does not appear to be valid.<br />';
  }
    $string_exp = "/^[A-Za-z .'-]+$/";
  if(!preg_match($string_exp,$first_name)) {
    $error_message .= 'The First Name you entered does not appear to be valid.<br />';
  }
  if(!preg_match($string_exp,$last_name)) {
    $error_message .= 'The Last Name you entered does not appear to be valid.<br />';
  }
  if(strlen($comments) < 2) {
    $error_message .= 'The Comments you entered do not appear to be valid.<br />';
  }
  if(strlen($error_message) > 0) {
    died($error_message);
  }
    $email_message = "Form details below.\n\n";

    function clean_string($string) {
      $bad = array("content-type","bcc:","to:","cc:","href");
      return str_replace($bad,"",$string);
    }

    $email_message .= "First Name: ".clean_string($first_name)."\n";
    $email_message .= "Last Name: ".clean_string($last_name)."\n";
    $email_message .= "Email: ".clean_string($email_from)."\n";
    $email_message .= "State: ".clean_string($ip)."\n";
    $email_message .= "Comments: ".clean_string($comments)."\n";


// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n" .
'X-Mailer: PHP/' . phpversion();
if (!mail($email_to, $email_subject, $email_message, $headers))
{
    echo "failed to send message";
}  

?>

唯一没有做的就是从状态中抓取一个随机的ip。对于每个状态，即AL，AK，AZ等。我有大约150个不同的IP地址。所以，让我们说有人选择阿拉巴马州（AL）的状态，我希望它从与AL在同一行的数据库中随机选择和ip。它正在接收IP地址，但它总是向我发送相同的IP用于AL。

根据代码它应该这样做，因为ORDER BY RAND在那里

$query = $pdo->prepare("SELECT ip FROM vincer WHERE state = ? ORDER BY RAND() LIMIT 1");

我四处询问，有些人建议我在表格中需要另一个名称为id的列，所以这就是它应该是什么样的

-------+-------+---------------+
| id   | state |      ip       |
+------+-------+---------------+
|  1   | AL    | 67.100.244.74 |
|  2   | AK    | 68.20.131.135 |
|  3   | AZ    | 64.134.225.33 |
+------+-------+---------------+

他们说我需要id，所以我可以随机拉入ip。有谁知道我需要添加此ID的PHP代码，以使这一切都工作。任何帮助将不胜感激

谢谢大家

阿里

Answer 1

RAND()每次都会给出不同的值如果您不想这样，您可以提供固定种子值如果你是偏执狂，你每次都可以提供不同的种子价值。

SELECT ip FROM vincer WHERE state = ? ORDER BY RAND(UNIX_TIMESTAMP(NOW())) LIMIT 1

如果在一个州中很少有不同的ip，那么当ip的数量接近1时，看到相同ip的机会就会增加。
如果只有1，那么当然会返回。

您可以通过将查询更改为：

来查看使用的RAND()

SELECT @rand:= RAND() as rand, ip 
FROM vincer 
WHERE state = ? 
ORDER BY rand 
LIMIT 1

Answer 2

我以前也遇到过同样的问题

您可以使用 NEWID() 而不是 RAND() 函数

SELECT *
FROM Northwind.Orders 
ORDER BY NEWID()

ORDER BY RAND无法正常工作

2 个答案: