我在这里有一个基于我在API演示中看到的baseadapter。我想动态添加/删除列表中的项目,在这种情况下,从按钮调用的意图添加,并从列表视图中单击图像视图中删除。在这种情况下,我将添加/删除DATA []中的项目。 我在SO和谷歌上四处寻找各种AddItem()和/或Remove()方法,但对于这种情况并没有真正想出什么。任何帮助都会很棒。这是代码:
public class myActivity extends Activity{
private static final int CONTACT_PICKER_RESULT = 1001;
private static final String TAG = myActivity.class.getSimpleName();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
ListView lv = (ListView)findViewById(R.id.listView1);
lv.setAdapter(new myAdapter(this));
Button bAdd = (Button)findViewById(R.id.bAdd);
bAdd.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
........xxxx....xxxx....
}
public class myAdapter extends BaseAdapter{
private LayoutInflater mInflater;
public myAdapter(Context context) {
mInflater = LayoutInflater.from(context);
}
@Override
public int getCount() {
// TODO Auto-generated method stub
return DATA.length;
}
@Override
public Object getItem(int position) {
// TODO Auto-generated method stub
return position;
}
@Override
public long getItemId(int position) {
// TODO Auto-generated method stub
return 0;
}
@Override
public View getView(final int position, View convertView, ViewGroup parent) {
// TODO Auto-generated method stub
ViewHolder holder;
if (convertView == null) {
convertView = mInflater.inflate(R.layout.row,null);
holder = new ViewHolder();
holder.text = (TextView) convertView.findViewById(R.id.txtTitle);
holder.icon = (ImageView) convertView.findViewById(R.id.imgIcon);
convertView.setTag(holder);
} else {
// Get the ViewHolder back to get fast access to the TextView
// and the ImageView.
holder = (ViewHolder) convertView.getTag();
}
holder.text.setText(DATA[position]);
holder.icon.setImageResource(android.R.drawable.ic_delete);
return convertView;
}
}
static class ViewHolder {
TextView text;
ImageView icon;
}
//this will not be hard-coded, jsut included for clarity
private static final String[] DATA ={
"one","two","three" };
答案 0 :(得分:1)
如果你需要做的就是在DATA []数组中添加/删除项目,为什么不用简单的List
替换数组,例如由ArrayList
实现。
这将允许您为适配器编写单击处理程序,根据需要在列表中添加/删除项目。