Question

1.如何在设备刚刚打开时启动/打开应用程序？

2.当设备刚刚解锁/退出锁定状态时如何启动/打开应用程序？

（我的意思是，如何识别这些事件？）

10Q，

大卫

这是我的新代码：

在清单中：

<receiver
  android-permission="android.permission.RECEIVE_BOOT_COMPLETED"
  android:name="BootReciver" >
  <intent-filter >
      <action android:name="android.intent.action.BOOT_COMPLETED" />
      <action android:name="android.intent.action.SCREEN_ON" />
  </intent-filter>
</receiver>

在BootReciver.java中，我添加到了我的项目中：

package development.Grandpa;
import android.content.BroadcastReceiver;

    public class BootReciver extends BroadcastReceiver {
    public void onReceive(Context context, Intent intent) {
        Intent intent1 = new Intent(context, Grandpa.class);
        context.startActivity(intent1);      
    }
}

爷爷班是我的主要活动。

此外，我正在我的设备上直接运行代码，这就是我在LogCat中获得的内容：

?? - ?? ??：??：??。???：INFO /（）：无法打开日志设备'/ dev / log / main'：没有这样的文件或目录

我还尝试添加一个reciver用于启动，另一个用于ScreenOn（有两个类），如下所示：

<receiver
android:name="ScreenOnReciver" >
    <intent-filter >
    <action android:name="android.intent.action.SCREEN_ON" />
</intent-filter>
</receiver>

<receiver
android-permission="android.permission.RECEIVE_BOOT_COMPLETED"
android:name="BootReciver" >
<intent-filter >
    <action android:name="android.intent.action.BOOT_COMPLETED" />
</intent-filter>
 </receiver>

但它也没有帮助。

编辑：

这是我在logcat之后得到的：

1.运行应用程序

2.退出申请

3.锁定屏幕

4.解锁屏幕

11-13 23:59:26.140: ERROR/AndroidRuntime(3640): Set to default setting_6 : region=-   Duser.region=IL propRegn=IL
11-13 23:59:26.710: ERROR/AndroidRuntime(3649): Set to default setting_6 : region=-Duser.region=IL propRegn=IL
11-13 23:59:33.246: ERROR/power(244): *** set_screen_state 0
11-13 23:59:33.246: ERROR/SensorManager(244): unregisterListener:: all sensors,    listener = com.android.server.PowerManagerService$13@40517118
11-13 23:59:33.593: ERROR/LockPatternKeyguardView(244): Phone is boot completed. so can   send broadcast message for music player
11-13 23:59:35.286: ERROR/power(244): *** set_screen_state 1
11-13 23:59:35.286: ERROR/SensorManager(244): registerListener :: handle = 3  name=     GP2A Light Sensor delay= 200000 Listener=   com.android.server.PowerManagerService$13@40517118
11-13 23:59:35.286: ERROR/SensorManager(244): reg :: handle = 3
11-13 23:59:35.336: ERROR/LockPatternKeyguardView(244): Phone is boot completed. so can  send broadcast message for music player
11-13 23:59:36.360: ERROR/SlidingTab(244): onTouchEvent() : thresholdReached !
11-13 23:59:36.380: ERROR/KeyguardViewMediator(244): Phone is boot completed. so can   broadcast
11-13 23:59:36.400: ERROR/MTPRx(3319): In MtpReceiverandroid.intent.action.USER_PRESENT
11-13 23:59:36.410: ERROR/MTPRX(3319): Battery charging. plugType = 2
11-13 23:59:36.410: ERROR/MTPRx(3319): USB charging
11-13 23:59:36.416: ERROR/MTPRx(3319): usb is connected, set value in Settings.System,   result = true
11-13 23:59:36.416: ERROR/MTPRx(3319): usb mode = 0
11-13 23:59:36.416: ERROR/MTPRx(3319): usb debugging is enabled

Edit2：

我在logcat中只有这些“异常”：

11-14 00:22:15.313: WARN/WindowManager(244): android.view.InflateException: Binary XML  file line #7: Error inflating class <unknown>
11-14 00:22:15.313: WARN/WindowManager(244): Caused by: java.lang.reflect.InvocationTargetException
11-14 00:22:15.313: WARN/WindowManager(244): Caused by:   android.content.res.Resources$NotFoundException: Resource is not a Drawable (color or   path): TypedValue{t=0x2/d=0x1010059 a=-1}

Answer 1

您要做的是设置一个侦听这些操作的BroadcastReceiver。更多信息：

根据您的情况，你会有一个接收器

public class YourReceiver extends BroadcastReceiver {
    @Override
    public void onReceive(Context context, Intent intent) {
        Intent intent = new Intent(context, YourActivity.class);
        context.startActivity(intent);
    }
}

并在清单中注册：

    <receiver
        android-permission="android.permission.RECEIVE_BOOT_COMPLETED"
        android:name="YourReceiver" >
        <intent-filter >
            <action android:name="android.intent.action.SCREEN_ON" />
            <action android:name="android.intent.action.BOOT_COMPLETED" />
        </intent-filter>
    </receiver>

设备开启或解锁时启动应用程序

1 个答案: