首先,我想告诉您,我之前从未使用过XML作为数据源。
我有一个名为“answers.xml”的XML文件,我需要连接gridview,formview等...
<?xml version="1.0"?>
<Answers>
<AnswerSet>
<Answer questionId="MRN">4444</Answer>
<Answer questionId="FName">test</Answer>
<Answer questionId="LName">patient</Answer>
<Answer questionId="AddressPt">blah blah</Answer>
<Answer questionId="Governorate">xxxx</Answer>
<Answer questionId="InitialCSF">Negative</Answer>
<Answer questionId="Diagnosis"></Answer>
<Answer questionId="Description"> </Answer>
</AnswerSet>
<AnswerSet>
<Answer questionId="MRN">1</Answer>
<Answer questionId="FName">1</Answer>
<Answer questionId="LName">1</Answer>
<Answer questionId="AddressPt">1</Answer>
<Answer questionId="InitialCSF">Positive</Answer>
<Answer questionId="Diagnosis">dx</Answer>
<Answer questionId="Description"> </Answer>
</AnswerSet>
</Answers>
我需要一种方法来使用.NET
更改xml文件中的数据(编辑/删除)答案 0 :(得分:3)
如果您不想使用XmlDataSource
控件,还可以使用LINQ to XML从文件中创建数据源对象:
XDocument doc = XDocument.Load("somefile.xml");
var results = from answer in doc.Descendants("Answer")
select new
{
Question = answer.Attribute("questionId").Value,
Answer = answer.Value
};
GridView1.DataSource = results;
GridView1.DataBind();
答案 1 :(得分:2)
System.Web.UI.WebControls.XmlDataSource类将返回给定XML文件的ASP.NET DataSource。给定的链接包括示例代码和演练。
请注意,如果必须使用XML属性作为键,则XPath expressin将包含Answer[@MRN]
之类的内容。