需要一个脚本来编辑文件

Question

<?php
class DATABASE_CONFIG {
    public $default = array(
        'datasource' => 'Database/Mysql',
        'persistent' => false,
        'host' => 'hostname',
        'login' => 'username',
        'password' => 'password',
        'database' => 'database_name',
        'prefix' => '',
        //'encoding' => 'utf8',
    );
    public $test = array(
        'datasource' => 'Database/Mysql',
        'persistent' => false,
        'host' => 'hostname',
        'login' => 'username',
        'password' => 'password',
        'database' => 'database_name',
        'prefix' => '',
        //'encoding' => 'utf8',
    );
}

登录，密码和数据库中有一些默认值。如何编写脚本来编辑登录名，密码和数据库？

Answer 1

php文件包含您的示例文本：

kent$  awk '/login/{l++;if(l>1)gsub(/root/,"newLogin");} 
        /password/{p++;if(p>1)gsub(/xxx/,"newPwd");} 
        /database/{d++;if(d>1)gsub(/xxx/,"newDB");} 1' php
<?php
class DATABASE_CONFIG {

    public $default = array(
        'datasource' => 'Database/Mysql',
        'persistent' => false,
        'host' => 'localhost',
        'login' => 'root',
        'password' => 'xxx',
        'database' => 'xxx',
        'prefix' => '',
        //'encoding' => 'utf8',
    );

    public $test = array(
        'datasource' => 'Database/Mysql',
        'persistent' => false,
        'host' => 'localhost',
        'login' => 'newLogin',
        'password' => 'newPwd',
        'database' => 'cake_test_db',
        'prefix' => '',
        //'encoding' => 'utf8',
    );
}

这只会在$ default块之后更改块。并且，仅默认值将被更改。例如在$ test中，'database' => 'cake_test_db'该值不是默认的'xxx'，因此不会更改。

如果你愿意，你可以在变量中加入新值，并使用-v。

传递给awk

修改

如果你想改变所有的值，（包括$ default block），它会更容易，检查下面的行:(与上面相同，只会改变defalut值（root，xxx，xxx）。

kent$    awk '/login/{gsub(/root/,"newLogin");}                                                                                          
            /password/{gsub(/xxx/,"newPwd");}                                                                                            
            /database/{gsub(/xxx/,"newDB");} 1' php                                                                                      
<?php
class DATABASE_CONFIG {

    public $default = array(
        'datasource' => 'Database/Mysql',
        'persistent' => false,
        'host' => 'localhost',
        'login' => 'newLogin',
        'password' => 'newPwd',
        'database' => 'newDB',
        'prefix' => '',
        //'encoding' => 'utf8',
    );

    public $test = array(
        'datasource' => 'Database/Mysql',
        'persistent' => false,
        'host' => 'localhost',
        'login' => 'newLogin',
        'password' => 'newPwd',
        'database' => 'cake_test_db',
        'prefix' => '',
        //'encoding' => 'utf8',
    );
}

<强> EDIT2

这适用于您的新示例。

 sed '/login/{s/username/newLOGIN/}; /password/{s/password/newPWD/2}; /database/{s/database_name/newDB/}' php

    <?php
    class DATABASE_CONFIG {
        public $default = array(
            'datasource' => 'Database/Mysql',
            'persistent' => false,
            'host' => 'hostname',
            'login' => 'newLOGIN',
            'password' => 'newPWD',
            'database' => 'newDB',
            'prefix' => '',
            //'encoding' => 'utf8',
        );
        public $test = array(
            'datasource' => 'Database/Mysql',
            'persistent' => false,
            'host' => 'hostname',
            'login' => 'newLOGIN',
            'password' => 'newPWD',
            'database' => 'newDB',
            'prefix' => '',
            //'encoding' => 'utf8',
        );
    }

Answer 2

    #!/usr/bin/awk -f

    BEGIN {   FS="'"   

         usr[0] ="usr1"   ;  usr[1] = "user2" 
        pass[0] ="pass1"  ; pass[1] = "pass2" 
          db[0] ="db1"    ;   db[1] = "db2"
    }  
    {
    if ($2 == "login") { 
        $0="\t'login' => '" usr[u] "',"
        u++
    } 
    if ($2 == "password") { 
        $0="\t'password' => '" pass[p] "',"
        p++
    }
    if ($2 == "database") { 
        $0="\t'database' => '" db[d] "',"
        d++
    }
     print
    }