Question

标准示例：

class Author(models.Model):
  name = models.CharField(max_length=100)

class Book(models.Model):
  title = models.CharField(max_length=100)
  author = models.ForeignKey(Author)
  #... Many other fields ...

我想在Book更改页面中修改Author 我尝试使用InlineModelAdmin，但由于Book有很多字段，因此编辑起来并不容易这就是为什么我试图将链接指向作者/更改模板上的 children 。

<ul>
  <li><a href="{% url admin:content_scribpart_add %}">Add a Book</a></li>
{% for book in original.book_set.all %}
  <li><a href="{% url admin:myapp_book_change book.id %}">Edit {{ book }}</a></li>
{% endfor %}
</ul>

但是有几个问题

如何在Author表单

Book

如何使保存按钮返回相关的Author
我是在正确的轨道上吗？

Answer 1

是的，当然。

将author主键作为GET参数附加到您的网址：

<ul>
  <li><a href="{% url admin:content_scribpart_add %}?author={{ object_id }}">Add a Book</a></li>
{% for book in original.book_set.all %}
  <li><a href="{% url admin:myapp_book_change book.id %}?author={{ object_id }}">Edit {{ book }}</a></li>
{% endfor %}
</ul>

修改相应的ModealAdmin图书，覆盖response_add() and response_change()。请注意，我们还override formfield_for_forein_key以预先填充author字段：

from django.http import HttpResponseRedirect
from django.core.urlresolvers import reverse

class BookAdmin(admin.ModelAdmin):

    def formfield_for_foreignkey(self, db_field, request, **kwargs):
        if db_field.name == "author":                    
            try:
                author_pk = int(request.GET.get('author', ''),) 
            except ValueError:           
                pass
            else:
                kwargs["initial"] = Author.objects.get(pk=author_pk)

        return super(BookAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)

    def response_add(self, request, obj, post_url_continue=None):
        return HttpResponseRedirect(reverse('admin:myapp_author_change', args=(obj.author.pk,))
        )

    def response_change(self, request, obj, post_url_continue=None):
        return HttpResponseRedirect(reverse('admin:myapp_author_change', args=(obj.author.pk,))
        )

Django - 管理员：编辑没有inlineForm的子模型

1 个答案: