Question

我使用AlphabetIndexer，SectionIndexer，Custom CursorAdapter作为自定义ListView。以下是相同的代码。但是在滚动列表时我无法看到字母表。我还尝试了以下链接how to combine both DISPLAY_NAME and NUMBER in a customized CursorAdapter?

public class ContactListCustomCursorAdapter extends CursorAdapter implements
    SectionIndexer {

private LayoutInflater inflater;
private CursorsForContacts cursorsForContacts;
private AlphabetIndexer alphabetIndexer;

public ContactListCustomCursorAdapter(Context context, Cursor cursor) {
    super(context, cursor, true);
    inflater = LayoutInflater.from(context);
    cursorsForContacts = new CursorsForContacts(context);
    alphabetIndexer = new AlphabetIndexer(
            cursor,
            cursor.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME),
            " ABCDEFGHIJKLMNOPQRSTUVWXYZ");
    //alphabetIndexer.setCursor(cursor);
}

@Override
public void bindView(View view, Context context, Cursor cursor) {

    String contactId = setContactName(view, cursor);
    setContactPhoneNumbers(view, contactId);
    setContactEmails(view, contactId);
}

@Override
public View newView(Context context, Cursor cursor, ViewGroup parent) {
    final View view = inflater.inflate(R.layout.custom_contact_list_item,
            parent, false);

    return view;
}

private String setContactName(View view, Cursor cursor) {
    int username = cursor
            .getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME);
    TextView userName = (TextView) view.findViewById(R.id.userName);
    userName.setText(cursor.getString(username));

    return cursor.getString(cursor
            .getColumnIndex(ContactsContract.Contacts._ID));

}

private void setContactPhoneNumbers(View view, String contactId) {
    Cursor phoneCursor = cursorsForContacts.getPhoneNumberCursor(contactId);
    TextView phoneNumber = (TextView) view.findViewById(R.id.userNumber);
    while (phoneCursor.moveToNext()) {
        phoneNumber
                .setText(phoneCursor.getString(phoneCursor
                        .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)));
    }
}

private void setContactEmails(View view, String contactId) {
    Cursor emailCursor = cursorsForContacts.getEmailCursor(contactId);
    TextView userEmailId = (TextView) view.findViewById(R.id.userEmailId);
    while (emailCursor.moveToNext()) {
        userEmailId
                .setText(emailCursor.getString(emailCursor
                        .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA)));
    }
}

@Override
public int getPositionForSection(int section) {
    return alphabetIndexer.getPositionForSection(section);
}

@Override
public int getSectionForPosition(int position) {
    return alphabetIndexer.getSectionForPosition(position);
}

@Override
public Object[] getSections() {
    return alphabetIndexer.getSections();
}

}

我错过了什么吗？

Answer 1

您需要将android:fastScrollEnabled="true"添加到布局xml中的ListView。

Answer 2

对于OP来说可能为时已晚，但其他在这里遇到同样问题的人可能会受益......

在我的情况下，字母索引器是＆＃34;随机＆＃34;在某些情况下，在其他情况下没有在同一个屏幕上。

如果列表不是很长，则快速滚动，因此字母索引器将被暂停。确切的行为可以在FastScroller类中找到，它是AbsListView的帮助类。那里有一段代码决定＆＃34;列表是否很长＆＃34;

final boolean longList = childCount > 0 && itemCount / childCount >= MIN_PAGES;

MIN_PAGES定义为值为4.如果您的列表项计数不是至少4倍，则子数（可见行）快速滚动，因此不会出现字母索引器。

AlphabetIndexer不使用Custom ListView

2 个答案: